I want to display the column3 = 'ffff-jhj-01'
with distinct values from column1.
Select distinct(name),phone,phone_id
FROM `calldetails`
where phone_id='ffff-jhj-01'
I have tried above query but it displays only column3 = 'ffff-jhj-01'
not distinct of name.
If you want all columns with the distinct clause then try this query
Select distinct(name),phone,phone_id FROM `calldetails`
where
phone_id='ffff-jhj-01'
GROUP BY name
Group by will give you distinct first column, but remember you will not get distinct data for column two.
For this case you don't even need the distinct clause you can get same output with Group by alone, like
Select name,phone,phone_id FROM `calldetails`
where phone_id='ffff-jhj-01'
Group by name
output of both queries will be as follows
whereas if you go without Group by,
Select distinct(name),phone,phone_id FROM `calldetails`
where
phone_id='ffff-jhj-01'
then output will be as follows
Moreover you can get all the variants details of phone,ie column 2 with the following query
SELECT name, GROUP_CONCAT( phone ) , phone_id
FROM `calldetails`
WHERE phone_id = 'ffff-jhj-01'
GROUP BY name
LIMIT 0 , 30
But the phone field should be a text/varchar field
尝试:
Select distinct(name),phone,phone_id FROM `calldetails` where phone_id='ffff-jhj-01'
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