Scala idiom for comparing to java.lang.Long
Question
What's the Scala idiom for comparing a long literal with a boxed java.lang.Long? I've come up with
myLong == new java.lang.Long(42L)
but it looks dreadful, and I'm hoping there's some cute syntax I'm not aware of.
1 answers
solution1
5 ACCPTED 2013-11-06 18:52:05
Scala == uses .equals method internally. So it does boxing-unboxing automatically. As @Frank S. Thomas said the working way is
myLong == 42L
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