I have to search for multiple values in a field using mysql in codeigniter. Here follows my code.
In Controller
public function vpsearch()
{
$data['info'] = $this->psearch_m->emp_search_form();
$this->load->view("employer/result",$data);
}
IN Model
public function emp_search_form()
{
$skill = $this->security->xss_clean($this->input->post('ps_skills'));
$jrole = $this->input->post('ps_jobrole'));
if ( $jrole !== NULL)
{
return $this->db->get('js_edu_details');
$this->db->like('js_skills','$skill');
}
}
In view ie, (../employer/result)
foreach($info->result() as $row)
{
echo $row->js_id."<br/><br/>" ;
}
However I am getting all the records in 'js_edu_details' table instead of fields having searched 'skills'.
Where I am going wrong? Any help wud b appreciated, thanx in advance.
Try:
public function emp_search_form()
{
$skill = $this->security->xss_clean($this->input->post('ps_skills'));
//$skill = $this->input->post('ps_skills', true); other short way of getting the above result with `xss clean`
if ( $jrole !== NULL)
{
$this->db->like('js_skills',$skill); #remove the single quote around the `$skill`
$res = $this->db->get('js_edu_details');
echo $this->db->last_query(); #try to print the query generated
return $res;
}
}
Return
statement should be after the like
statement
You should arrange the code properly like this
public function emp_search_form()
{
$ps_skills = $this->input->post('ps_skills')
$skill = $this->security->xss_clean($ps_skills);
if ( $jrole !== NULL)
{
$this->db->like('js_skills','$skill');
return $this->db->get('js_edu_details');
}
}
Also you should note the condition will never meet. It will always give error undefined variable $jrole
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.