Linux bash script, how to use the data in the command

Question

$script location1 location2 

我是linux的新手，我试图制作一个bash脚本来移动数据，该脚本将像上面一样使用，我只是想知道如何将这些位置放入脚本中以进行修改。

Answer 1

Not sure what you are asking, but if you want to access command line arguments in a bash script you can do so by using the variables $1 - $n. They are numbered in the order you passed them to the script.

See here for some examples

Answer 2

If you call the script using the command line

$ script location1 location2

you can access the value of the two arguments using $1 and $2 . That is, if you script looks like

from=$1
to=$2
echo "Move files from $from to $to"

the output resulting from the above command line would be

Move files from location1 to location2

Note that you don't need to set from and to ; you can use $1 and $2 anywhere you would another variable.

Answer 3

you can use variables $1, $2, ... for example, $script location1 location2 then in your script, you can get location1 as $1.

Here is a cool guide: http://mywiki.wooledge.org/BashGuide/Parameters#Special_Parameters_and_Variables

Answer 4

Within your bash script you can simply use the "mv" command to move your data, like so:

mv path/location1 path/location2

That's it!

If, in your script you first go to the directory containing the location1 data, you won't need to provide the path on the first one, like so:

cd path/

mv location1 path/location2