get field value in the same row where MAX(Field) LIMIT 1

Question

i have a table called 'App' contains

---

ID | Name | Developer | price | downloads


1 | App1 | App Developer | Free | 5

---

i am using this code to get max downloads

mysql_connect("$host", "$username", "$password") or die(mysql_error());

mysql_select_db("$database") or die(mysql_error());

$mostappdownloaded = mysql_query("SELECT MAX(downloads) as maxdownloads FROM app")
or die(mysql_error());

while($infomostdownloadapps = mysql_fetch_array( $mostappdownloaded )) {
    echo $infomostdownloadapps['maxdownloads']; 
}

i want to get the developer field value from the row that contains max downloaded app

any help ?

Answer 1

NO need to do fancy things just add developer in your query and you will get your desired output.

$mostappdownloaded = mysql_query("SELECT MAX(downloads) as maxdownloads,Developer 
FROM app ")

Answer 2

try this with a subquery

SELECT Developer FROM App WHERE downloads = (SELECT MAX(downloads) as maxdownloads FROM app);

It can be possible that there are several records with the same max numbers of downloads

Answer 3

SELECT Developer FROM App ORDER BY downloads DESC LIMIT 1

Answer 4

您可以从下面的查询中简单地获取开发者在哪个应用程序中拥有最大下载量

select developer from app where downloads = (select max(downloads) from app)