Currently i need to convert mp4 video to webm and ogg . To convert mp4 to webm i have used "ffmpeg.exe". I am running following code to convert video mp4 to webm.
[DllImport("User32.dll")]
public static extern bool SetForegroundWindow(IntPtr hWnd);
public void mciConvertWavMP3(string fileName, bool waitFlag)
{
string savepath = Server.MapPath(fileName);
string destpath = Server.MapPath(fileName);
string pworkingDir = Server.MapPath("~/ffmpeg/");
// string outfile = "-b:a 16 --resample 24 -m j " + savepath + " " + savepath.Replace(".wav", ".mp3") + ""; //--- lame code
// string outfile = "-b 192k -i " + savepath + " " + destpath.Replace(".mp4", ".webm");
// string outfile = "ffmpeg -i " + savepath + " -acodec libvorbis -ac 2 -ab 96k -ar 44100 -b 345k -s 640x360 " + Server.MapPath("output-file.webm");
string outfile = "ffmpeg -i \"test7.mp4\" -c:v libvpx -crf 10 -b:v 1M -c:a libvorbis \"" + Server.MapPath("output-file.webm") + "\"";
// string outfile = "ffmpeg -i \""+fileName+"\" -codec:v libvpx -quality good -cpu-used 0 -b:v 600k -qmin 10 -qmax 42 -maxrate 500k -bufsize 1000k -threads 2 -vf scale=-1:480 -an -pass 1 -f webm /dev/null";
System.Diagnostics.ProcessStartInfo psi = new System.Diagnostics.ProcessStartInfo();
psi.FileName = pworkingDir+"ffmpeg.exe";
psi.Arguments = outfile;
psi.UseShellExecute = true;
psi.CreateNoWindow = false;
System.Diagnostics.Process p = System.Diagnostics.Process.Start(psi);
Thread.Sleep(1000);// utput.webm
if (waitFlag)
{
p.WaitForExit();
// wait for exit of called application
}
}
I kept my project folder in D:/ drive
When i am running from Command promt its working fine. But when i am running this code its not working fine.
Formal errors which i am getting are :
" unable to find a suitable output format for 'ffmpeg' " kind of errors. SO please can any one help to solve this issue.
Thank & Regards
remove "ffmpeg" from the
string outfile = "ffmpeg -i \"test7.mp4\" -c:v libvpx -crf 10 -b:v 1M -c:a libvorbis \"" + Server.MapPath("output-file.webm") + "\"";
you already pass app name in psi.FileName variable.
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