I have started to learn the Qt 5 and got stuck at one point for a long time.
I have two classes. ScoreHandler handles a list of ScoreRecords. I create those two classes in C++ and set an instance of ScoreHandler as a context property. Now in QML I can assign the model, but the delegate can not see properties of ScoreRecord. Do I have to register something somewhere? Please help me.
scorerecord.h
class ScoreRecord : public QObject
{
Q_OBJECT
Q_PROPERTY(QString name READ name WRITE setName NOTIFY nameChanged)
Q_PROPERTY(QString date READ date WRITE setDate NOTIFY dateChanged)
Q_PROPERTY(QString score READ score WRITE setScore NOTIFY scoreChanged)
public:
ScoreRecord(QObject *parent = 0);
ScoreRecord(const QString& n, const QString &d, const QString &s, QObject *parent = 0);
QString name() const;
void setName(const QString &str);
QString date() const;
void setDate(const QString &str);
QString score() const;
void setScore(const QString &str);
signals:
void nameChanged();
void dateChanged();
void scoreChanged();
public slots:
private:
QString m_name;
QString m_date;
QString m_score;
};
scorehandler.h
class ScoreHandler : public QObject
{
Q_OBJECT
private:
const char* SCORE_TABLE_FILENAME;
struct scoreRow {
char name[128];
char date[32];
char score[16];
};
public:
explicit ScoreHandler(QObject *parent = 0);
QList<ScoreRecord *> scoreList;
signals:
public slots:
void SaveScore(const QString &name, const QString &date, const QString &score);
void LoadScore();
};
main.c
int main(int argc, char *argv[])
{
QGuiApplication app(argc, argv);
QtQuick2ApplicationViewer viewer;
ScoreHandler* scoreHandler = new ScoreHandler();
QQmlContext* ctx = viewer.rootContext();
ctx->setContextProperty("MyScoreModel", QVariant::fromValue(scoreHandler->scoreList));
viewer.setMainQmlFile(QStringLiteral("qml/qmlListView/main.qml"));
viewer.showExpanded();
return app.exec();
}
QML file
import QtQuick 2.0
Rectangle {
width: 360
height: 360
ListView {
width: 100; height: 100
anchors.fill: parent
model: MyScoreModel
delegate: Text {
text: name
}
}
}
And please can somebody explain me, why the following code works? What is the reason?
main.c
int main(int argc, char *argv[])
{
QGuiApplication app(argc, argv);
QtQuick2ApplicationViewer viewer;
ScoreHandler* scoreHandler = new ScoreHandler();
QList<QObject *> scoreList;
scoreList.append(new ScoreRecord("Jmeno1", "datum1", "score1"));
scoreList.append(new ScoreRecord("Jmeno2", "datum2", "score2"));
scoreList.append(new ScoreRecord("Jmeno3", "datum3", "score3"));
QQmlContext* ctx = viewer.rootContext();
ctx->setContextProperty("MyScoreModel", QVariant::fromValue(scoreList));
viewer.setMainQmlFile(QStringLiteral("qml/qmlListView/main.qml"));
viewer.showExpanded();
return app.exec();
}
I believe there is a cleaner way of doing it. You need to define a property scoreList on your ScoreHandler:
Q_PROPERTY(QQmlListProperty<ScoreRecord> scoreList READ scoreList)
And a private variable that holds your ScoreRecord pointers:
QList _scoreRecords;
Then you need to implement the accessor method:
// ScoreHandler.h
QQmlListProperty<ScoreRecord> scoreList();
// ScoreHandler.cpp
QQmlListProperty<ScoreRecord> ScoreHandler::scoreList()
{
return QQmlListProperty<ScoreRecord>(this, _scoreRecords);
}
You can then access it from qml.
There is an example on QtCreator about this. It is called Extending QML - Object and List Property Types Example
I strongly believe that
ctx->setContextProperty("MyScoreModel", QVariant::fromValue(scoreHandler->scoreList));
performs a copy of your current list, which is empty in the example given, and is not updated when you modify scoreList
. Qt doc says:
Note: There is no way for the view to know that the contents of a QList has changed. If the QList changes, it is necessary to reset the model by calling QQmlContext::setContextProperty() again.
If you need real data model, derive from QAbstractListModel
and implement necessary overrides: data(...)
, rowCount()
and count
property, roleNames()
.
The last sample works because it assigns static list to context variable. Same as in JavaScript:
[{name: Jmeno1, date: datum1, score: score1},
{name: Jmeno2, date: datum3, score: score2},
{name: Jmeno3, date: datum3, score: score3}]
Nuno Santos answer is good, I would also point two important modifications you may need:
Note that ScoreRecord must be registered with the QML type system, eg.: qmlRegisterType<ScoreRecord>("com.mycompany.database", 1, 0, "ScoreRecord");
and if ScoreRecord is in namespace, you have to define property like this:
Q_PROPERTY(QQmlListProperty<myNamespace::ScoreRecord> scoreList READ scoreList)
请注意,如果ScoreRecord
在命名空间中,您可能必须像这样声明 Q_PROPERTY。
Q_PROPERTY(QQmlListProperty<myNamespace::ScoreRecord> scoreList READ scoreList)
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