PHP Session won't work after refresh
Question
I've tried adding a PHP session, so they don't have to fill in the same password all the time. If I go to the page and fill in the code it will show the page with the correct session but when I refresh the page the session is gone.
Code of the session:
<head>
<script>
{ background-color:#87CEFA; }
</script>
</head>
<?php
error_reporting(0);
session_start();
$_SESSION["pass"] = $_POST["code"];
$pass = $_POST["code"];
$con=mysqli_connect("localhost","bb","$pass","bb");
if (mysqli_connect_errno($con))
{
echo "Kan geen verbinding maken, de ingevulde code is verkeerd of de server is offline!";
echo 'Hello '.$_SESSION["pass"].'!';
}
$result = mysqli_query($con,"SELECT * FROM ftp");
while($row = mysqli_fetch_array($result))
{
$myuser = $row['user'];
$mypass = $row['pass'];
$myhost = $row['host'];
$conn_id = ftp_connect($myhost) or die("Couldn't connect to $myhost");
if (@ftp_login($conn_id, $myuser, $mypass))
{
//Path to your *.txt file:
$file = $ftp_server['DOCUMENT_ROOT'] . "bbbb";
$contents = file($file);
$string = implode($contents);
echo $string;
}
}
mysqli_close($con);
?>
Thanks.
4 answers
solution1
0
On every page load you are running the code $_SESSION["pass"] = $_POST["code"]; . Then you try to echo it like echo 'Hello '.$_SESSION["pass"].'!'; . What you are essentially doing is echoing $_POST["code"] . Only when you submit the form will the $_POST variable be set.
solution2
0 2013-11-29 15:29:19
You're overwriting your session variable on each page load. You need to check if the form was submitted before setting your session variable:
session_start();
$_SESSION["pass"] = $_POST["code"];
needs to be
session_start();
if ('POST' === $_SERVER['REQUEST_METHOD']) {
$_SESSION["pass"] = $_POST["code"];
}
solution3
0 2013-11-29 16:22:37
- You should check that your server configured correctly. Check session storage and stored data
- You should start session before any output (check where you start session and you don't have space after ?>). Overriding of super globals values is bad practise
solution4
0 2013-11-30 12:40:28
I'm sorry to say this but you seriously need to read more on php sessions .
I took some liberties rewriting and commenting but if there's anything you don't understand, please ask
combo script
<?php
// protect against any output, leave no spaces or shenanigans before the session_start()
// even warnings and errors
// this is the first thing that has to happen BEFORE ANY OUTPUT
session_start();
// is this a good idea when you're in development
error_reporting(0);
// we don't know if $_POST['whateva'] actually exists
if (isset($_POST['code'])) {
// this may not be such a good idea...
$_SESSION['pass'] = $_POST['code'];
}
$pass = isset($_POST['code']) ? $_POST['code'] : '';
$error = '';
try {
$con = mysqli_connect('localhost','bb',$pass,'bb');// is this barebones MVC? just curious
if (mysqli_connect_errno($con)) throw new Exception('Kan geen verbinding maken, de ingevulde code is verkeerd of de server is offline! Hello '.$_SESSION['pass'].'!');
$result = mysqli_query($con,'SELECT * FROM ftp');
$ftpContent = array();
while ($row = mysqli_fetch_array($result)) {
$myuser = $row['user'];
$mypass = $row['pass'];
$myhost = $row['host'];
if (!$conn_id = ftp_connect($myhost)) throw new Exception('Couldn\'t connect to '.$myhost);
if (@ftp_login($conn_id,$myuser,$mypass)) {
//Path to your *.txt file:
$file = $ftp_server['DOCUMENT_ROOT'].'bbbb';// where does this $ftp_server come from????
$contents = file($file);
$string = implode($contents);
$ftpContent[$myuser] = $string;
}
}
mysqli_close($con);
} catch (Exception $e) {
$error = $e->getMessage();
}
// now output all your stuff here
?>
<!DOCTYPE html>
<html>
<head>
<style>body{background-color:#87cefa;}.error{color:#f00;}</style>
</head>
<body>
<?php if ($error) echo '<p class="error">There has been an error: '.$error.'</p>'; ?>
</body>
</html>
Don't copy paste this, look up what was done and evaluate what will happen, there's also a missing variable so you have to take care of that
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