Hello This may looks to be simple task but I am getting struck... In my application i am getting an array which would be like
Array
(
[0] => Array
(
[home_id] => 1
[distance] => 12
)
[1] => Array
(
[home_id] => 3
[distance] => 14
)
[2] => Array
(
[home_id] => 94
[distance] => 1.679713069
)
.
.
.
.
)
And my table looks like
home_id | home_name
1 | My home 1
2 | My home 2
3 | My home 3
From this array i will get the home_id which is in database table. So How can i get the result details which includes the home_name and the distance from the first array which might be like
home_name | distance
___________________________
My home 1 | 0.562620830044
My home 3 | 14
Thank you in advance
Loop through your array and get the home_name
from database using codeigniter active record
query -
foreach($yourArray as $row)
{
$id = $row['home_id'];
$distance = $row['distance'];
$db_result = $this->db->get_where('yourtable', array('home_id' => $id));
if($db_result && $db_result->num_rows() > 0){
$result = $db_result->row();
$home_name = $result->home_name;
}
}
If you cannot JOIN
the two tables in one query and have to use that array then you can do:
foreach($yourArray as $home)
{
$id=$home["home_id"];
$distance=$home["distance"];
$id=intval($id);
$sql="SELECT home_name FROM yourTable WHERE home_id=$id"; // execute this query to get name
}
From this array i will get the home_id which is in database table. So How can i get the result details which includes the home_name and the distance from the first array which might be like
If you want to get home details
from table home_details_table
using the id
you get from the main array, so replace the field home_name
in home_details_table
by home_id
and link both tables as a One to Many
relation.
home_table:
home_id | home_name
1 | My home 1
2 | My home 2
3 | My home 3
home_detail_table:
home_id | distance
1 | 0.562620830044
3 | 14
Then with a JOIN
, you will be able to do :
foreach($mainArray as $home)
{
$id = $home["home_id"];
$sql="SELECT h.home_id, h.home_name, d.home_distance FROM home_table h JOIN home_details_table d ON h.home_id = d.home_id WHERE h.home_id = ".$id;
// with this query you will have the name and distance of the given home id.
}
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