selective input using scanf

Question

From an input of n numbers(value of n is known) separated by spaces, eg(here n is 6): 3 5 8 9 13 2

If I wish to accept only the 2nd and the 5th number and ignore the rest, how do I do it using scanf?

I found accepting the numbers in an array and using only the required ones a bit redundant, so I'm looking for a smarter alternative.

Answer 1

Try this

int num,number1,number2;
for(int i = 0; i < 6; i++)
{
    scanf("%d", &num);
    if(i == 1)
         number1 = num;
    if(i == 4)
         number2 = num;
}

Answer 2

scanf("%*d%d%*d%*d%d%*d", &firstNumber, &secondNumber);

Try this.

%*d reads the value, but ignores it in the name of good will.

Answer 3

If the knwon number n is a fix number (n=6 always)

then you can use the following scanf

int a2, a5;
scanf("%*d %d %*d %*d %d %*d", &a2, &a5 );

Answer 4

I would read every number using scanf . Read not required ones in some temp variable and others in array or any variable (as required)

Answer 5

scanf("%*d %d %*d %*d %d %*d", &i, &j)

Answer 6

int v[6];
scanf( "%d %d %d %d %d %d", &v[0], &v[1], &v[2], &v[3], &v[4], &v[5] );

v[1] and v[4] contain the answers from your example.