printing 2 columns in a table while in for loop

Question

I am trying to print results from a mysql query in a table that will be in 2 columns. to do this through my for loop i did the following:

    $num = 1;
            while($r = $qry->fetch())
            {
                    if (!fmod($num,2)) echo '<tr>';
                    echo "<td>" . $num . "</td>";
                    if (!fmod($num,2)) echo '</tr>';
                    $num++;
           }

however, each row is getting its own row in the table. even though $num is printed and shows 1,2,3,4 and so on. what am i missing?

Answer 1

You got it almost right, but each iteration needs to EITHER display a <tr> OR an </tr> so:

https://eval.in/93455

$num = 1;
        while($num < 11)
        {
                if (fmod($num,2)) echo '<tr>';
                echo "<td>" . $num . "</td>";
                if (!fmod($num,2)) echo '</tr>';
                $num++;
       }

Note I altered your while condition for test purposes

Answer 2

I would recommend that you do this instead. It creates a table, and lists column1 and column2 for each row.

    $result
        ?>
         <table>
          <tr>
           <th> Data for column 1</th>
          </tr>
         <tr>
        <?
        while($row = mysqli_fetch_assoc($result))
        {

          echo "<td>".$row['dataforcolumn1']."</td>";
        }
    ?>
</tr>
    </table>

Answer 3

I would simplify it with doing this:

$num = 1;
            while($r = $qry->fetch_array())
            {
                    if(fmod($num,2)) echo "</tr>\n";
                    echo "<td>" . $r['columnName'] . "</td>\n";
                    if(!fmod($num,2)) echo '</tr>';
                    $num++;
           }

Mainly, this is changing the fmod command to be divisible by 2 to end the tag as you want it to add that after there are two tags added (meaning it SHOULD be divisible by 2).