PHP Regular expression to check 3 digits followed by alpha

Question

I want to validate a string if and only if meets two conditions:

a. String is exactly 7 characters in length

b.The string format is NNNANNA (N represents digit(0-9) and A alphabet(az,AZ).

Currently I am doing this:

if(preg_match('^d{3}\[a-zA-Z]\d{2}\[a-zA-Z]$', $str) and strlen($str)==7)
{
do something
}

But I am getting this error:

Warning: preg_match(): No ending delimiter '^' found in C:\\wamp\\www\\warrant\\yourproducts\\let.php on line 2

What am I missing?

PS I am horrible with reg expressions.

Ahmar

Answer 1

Your regex is wrong. It should be:

'/^\d{3}[a-zA-Z]\d{2}[a-zA-Z]$/'

OR

'/^\d{3}[a-z]\d{2}[a-z]$/i'

Answer 2

'/^\d{3}[a-zA-Z]\d{2}[a-zA-Z]$/'