I have a link button ( the text of the link button is edit ) in a gridview , i give it a commandname call modify
So in my design the code is :
<asp:TemplateField>
<ItemTemplate>
<asp:LinkButton ID="LinkButton1" runat="server" CommandName="modify">Edit</asp:LinkButton>
</ItemTemplate>
</asp:TemplateField>
And in my code behind is :
protected void GridView1_RowCommand(object sender, GridViewCommandEventArgs e)
{
LinkButton linkBtn = (LinkButton)sender;
if (linkBtn.CommandName == "modify") // tried linkBtn.CommandArguemtn , doesn't help
{
Panel1.Visible = true;
int index = Convert.ToInt32(e.CommandArgument);
Label login = (Label)GridView1.Rows[index].Cells[0].FindControl("Label1");
//Things i want to do
}
}
As you can see i set the panel to be visible , but it won't appear ... am i doing the correct way? i know of an alternative which is to use the default edit button generated , but i don't want to do that . I am trying to put a link button in a gridview and click on the link button and then panel ( consists of textboxs controls ) should appear then make changes of the gridview data in the panel .
just use
protected void GridView1_RowCommand(object sender, GridViewCommandEventArgs e)
{
if (e.CommandName == "modify")
{
Panel1.Visible = true;
int index = Convert.ToInt32(e.CommandArgument);
Label login = (Label)GridView1.Rows[index].Cells[0].FindControl("Label1");
//Things i want to do
}
}
you wont need to check the button first, e.CommandName
will be sufficent
Try like this.use the CommandName
property to specify or determine the command name MSDN
protected void GridView1_RowCommand(object sender, GridViewCommandEventArgs e)
{
if(e.CommandName=="modify")
{
\\
}
}
Use the following code
protected void GridView1_RowCommand(object sender, GridViewCommandEventArgs e)
{
if (e.CommandName.ToLower()== "modify")
{
Panel1.Visible = true;
int index = Convert.ToInt32(e.CommandArgument);
Label login = (Label)GridView1.Rows[index].Cells[0].FindControl("Label1");
//Things i want to do
}
}
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