java : finding absolute xpath of specific node
Question
Is it possible to find xpath of any specific node of XML or XHTML file ?
For (eg)
<html>
<body>
<div id="a">
<div>
</div>
<div class"b">
<div>
//I want xpath of below line only
<a id="c">Here </a>
</div>
</div>
</div>
</body>
</html>
As shown above, if I want xpath of <a id="c">Here </a> line only. Answer should be like :- /html/body/div/div[2]/a[@id="c"] Is it possible? If yes, could you pls provide code ? Thanks in advanced. :)
1 answers
solution1
1 2014-01-29 12:37:49
In XPath 3.0 there is a function path() which does roughly what you want, though not precisely (how is the processor supposed to know that you want the predicate [@id="c"] included?)
It's easy enough in XSLT to do something like this:
<xsl:template match="*[@id]" mode="path">
<xsl:next-match/>
<xsl:value-of select="concat('[@id="', @id, '"]')"/>
</xsl:template>
<xsl:template match="*[last()!=1]" mode="path">
<xsl:next-match/>
<xsl:text>[</xsl:text>
<xsl:number/>
<xsl:text>]</xsl:text>
</xsl:template>
<xsl:template match="*" mode="path">
<xsl:apply-templates select="parent::*" mode="path"/>
<xsl:text>/</xsl:text>
<xsl:value-of select="name()"/>
</xsl:template>
and if you really have to do it in Java, you can either invoke the above XSLT from Java or rewrite it. For a completely general solution though, you need to worry about namespaces, and what you do about namespaces depends on why you want the path in the first place: is it intended for human readers or for software?
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