Within CakePHP 2 I am using pagination which works great until I see the URL which is page:2, how can I make this ?page=2 ?
The next question is that I use this code for my controller which powers /domain.com/offers/top, /domain.com/offers/newest, /domain.com/offers/popular and then the categories like /domain.com/offers/tv-and-video. The thing is when it is paginated for /domain.com/offers/top instead of being /offers/top/page:2 it goes to /offers/bycategory/top/page:2.
public function bycategory($slug = null)
{
$userId = $this->Session->read("UserAuth.User.id");
if ($slug == 'top') {
//Get the top rated offers
$this->paginate = array(
'limit' => 15,
'order' => array(
'Offer.vote' => 'desc'
)
);
} elseif ($slug == 'newest') {
//Get the latest offers
$this->paginate = array(
'limit' => 15,
'order' => array(
'Offer.created' => 'desc'
)
);
} elseif ($slug == 'popular') {
//Get the most talked about offers
} else {
//This is the categories, so just get the category slug.
$this->paginate = array(
'conditions' => array('Category.slug =' => $slug),
'limit' => 15,
'order' => array(
'Offer.created' => 'desc'
)
);
}
$offers = $this->paginate('Offer');
// pass the value to our view.ctp
$this->set('offers', $offers);
$this->set('userId', $userId);
$this->render('/Offers/index');
}
This is my custom route:
Router::connect(
'/offers/:catslug',
array('controller' => 'offers', 'action' => 'bycategory'),
array(
'pass' => array('catslug')
));
how can I make this ?page=2 ?
By setting the paramType
option in paginator component options as mentioned in manual .
You second issue looks like reverse routing issue. Have you setup any custom routes?
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.