SQL Syntax Error in PHP

Question

I keep getting the following error in PHP: "You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near

'IN (SELECT invoiceNo FROM sales2012 GROUP BY invoiceNo HAVING COUNT(invoiceNo)>1' 
at line 1

My query is as follows:

$query = "SELECT invoiceNo, invoiceDate, dueDate, customerID, customerName, 
dateTrans, postDate, description, grossSale, vat, netSale, quantity, 
branch, despatchNote 
FROM 
sales2012 WHERE invoiceNo IN (
    SELECT invoiceNo FROM sales2012 GROUP BY invoiceNo HAVING COUNT(invoiceNo)>1)";

When I run a simple query like SELECT * FROM sales2012 I get the perfect result and even when I run the query up until the IN clause it runs as well. For some reason it crashes when I run the whole thing.

I also ran the same code using SQL Workbench and it printed out the table that I was looking for. I know the code works, I just can't figure out why it doesn't work in PHP.

I also changed the execution time but that didn't work either.

Any help would be much appreciated. Thanks

Answer 1

the correct query is :

 $query = "SELECT invoiceNo, invoiceDate, dueDate, customerID, customerName, dateTrans, postDate, description, grossSale, vat, netSale, quantity, branch, despatchNote 
           FROM sales2012 
           WHERE invoiceNo IN (SELECT invoiceNo FROM sales2012 GROUP BY invoiceNo HAVING COUNT(invoiceNo)>1)";

but the better query is:

   $query = "SELECT invoiceNo, invoiceDate, dueDate, customerID, customerName, dateTrans, postDate, description, grossSale, vat, netSale, quantity, branch, despatchNote 
           FROM sales2012 s1
           INNER JOIN (SELECT invoiceNo FROM sales2012 GROUP BY invoiceNo HAVING COUNT(invoiceNo)>1) 
           as s2 on s2.invoiceNo = s1.invoiceNO";

Answer 2

If you look at this:

FROM sales2012 IN (SELECT invoiceNo 

You will see that something is missing. It should resemble

FROM sales2012 
where somefield IN (SELECT invoiceNo