memset with 0 and 0X00

Question

Is there any difference in the below lines:

char myname[512]; -- created a character array and wants to memset it.

Is there any difference in the below two lines.

memset (&myname, 0x00, sizeof(myname));
memset (&myname, 0, sizeof(myname));

I am pretty sure that both will nullify the myname array.

Answer 1

The 0x00 syntax is for the programmer only. There will be no difference in the compiled code.

I you want to try the experiment yourself quickly you could use gcc explorer .

You would see that the generated assembly is identical.