Retrieve data from mysql and show in html table

Question

I have a table "data" , in that I have a column "name" there are many names saved in name column in the table name "data" NOW what I want is print out the record some thing like this but using PHP mysql_fetch_array() and loop through it. (while loop)

Results:

<table>
  <tr>
    <td>name</td><td>name</td>
  </tr>
</table>

Edit: Here is my current code -

<ul class="spa1" style="margin-left:5px">
<?php               

        $img= mysql_query("SELECT * FROM immi");
        while ($row=mysql_fetch_array($img)){
            echo "<li><a href='PracticeArea.php?cat=ts&id=".$row['id']."'>".$row['name']."</a></li>";
            }?>

</ul>

and what I want is something like this:

<ul class="spa1" style="margin-left:5px">
<?php               

        $img= mysql_query("SELECT * FROM immi");
        while ($row=mysql_fetch_array($img)){
 echo "<li><a href='PracticeArea.php?cat=ts&id=".$row['id']."'>".$row['name']."</a></li>
<li><a href='PracticeArea.php?cat=ts&id=".$row['id'] + 1."'>".$row['name']."</a></li>
";
            }?>

Answer 1

<table><tr>
<?php
$i = 0;
$img = mysql_query("SELECT * FROM immi");
while ($row=mysql_fetch_array($img)) {
  if (($i % 2) == 0 && $i > 0) echo '</tr><tr>';
    echo "<td><a href='PracticeArea.php?cat=ts&id=".$row['id']."'>".$row['name']."</a></td>";
  ++$i;
  }
if (($i % 2) == 1) echo '<td>&nbsp;</td>';
?>
</tr></table>