Here I am trying to get some data from database and want to display it as a json response so that user can fetch each field.
Here is how user can perform query
http://localhost/safari/index.php?getbranch=true
this should give branch details from tables.
Here is PHP code to do it
<?php
if(isset($_GET['getbranch']))
{
$getbranch = $_GET['getbranch'];
if($getbranch == 'true')
{
getbranch($getbranch);
}
}
function getbranch($getbranch)
{
$con = mysqli_connect('127.0.0.1', 'root', '', 'safari');
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
return;
}
$today = date("Ymd");
$result = mysqli_query($con,"SELECT division, branch,branchofficename,branchofficecode,status from tbl_branchoffice");
while ($row = @mysqli_fetch_array($result))
{
$result1 = json_encode($row);
}
echo $result1;
}
What's wrong wit this?
JSON response:
[{"0":"3","sno":"3","1":"2","division":"2","2":"2","branch":"2","3":"SAFFARI TRAVELS","branchofficename":"SAFFARI TRAVELS","4":"gfgbhghfhf","branchofficecode":"gfgbhghfhf","5":"active","status":"active"},
{"0":"4","sno":"4","1":"2","division":"2","2":"chennai","branch":"chennai","3":"chennai","branchofficename":"chennai","4":"br01","branchofficecode":"br01","5":"active","status":"active"},{"0":"5","sno":"5","1":"3","division":"3","2":"delhi","branch":"delhi","3":"delhi","branchofficename":"delhi","4":"br02","branchofficecode":"br02","5":"notactive","status":"notactive"},{"0":"6","sno":"6","1":"2","division":"2","2":"bangalore","branch":"bangalore","3":"bangalore","branchofficename":"bangalore","4":"br03","branchofficecode":"br03","5":"active","status":"active"},{"0":"7","sno":"7","1":"3","division":"3","2":"pune","branch":"pune","3":"pune","branchofficename":"pune","4":"br04","branchofficecode":"br04","5":"notactive","status":"notactive"}]
$result1 = array();
if(isset($_GET['getbranch']))
{
$getbranch = $_GET['getbranch'];
if($getbranch == 'true')
{
getbranch($getbranch);
}
}
function getbranch($getbranch)
{
$con = mysqli_connect('127.0.0.1', 'root', '', 'safari');
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
return;
}
$today = date("Ymd");
$result = mysqli_query($con,"SELECT division,
branch,branchofficename,branchofficecode,status from tbl_branchoffice");
while ($row = @mysqli_fetch_array($result))
{
$result1[] = $row;
}
echo json_encode($result1);
}
First collect each row from the result into the array result1 and then finally output the json_encode of $result1 array
Change your while
loop
$result1 = array();
while ($row = @mysqli_fetch_array($result))
{
array_push($result1 , $row);
}
by doing so, you have collected all result in $result1
now you can encode it
echo $result1 = json_encode( $result1);
I will prefer to use array
, ignor json_encode
line code,
foreach($result1 as $resultset){
//resultset contains one single row of table
foreach($resultset as $column => $columnValue){
//assuming your table column name as 'city'
if($column == 'city' && $columnValue == 'pune' ){
//displaying array of table which satisfies the condition
var_dump($resultset );
}
}
}
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