I'm trying to post the value into textbox, depending on the value of my other textbox. Just for ie I input pencil in try1 field, the value should show in try2 field is A00003. I got it in alert message. But the problem is there's no value returning in textbox try2. What is the problem with this?
Any help will appreciate.
Table Structure
Item | Item_Code
Pencil | A00003
Ballpen | A00004
index.php
<input id="try1" name="try1">
<input id="try2" name="try2">
<script type="text/javascript">
$(document).ready(function()
{
$('input[id="try1"]').change(function()
{
var try1 = $("#try1").val();
$.ajax({
type: "POST",
url: "getajax.php",
data :"try1="+try1,
dataType:'html',
type:'POST',
success:function(data){
alert(data)
$('#try2').html(data);
}
});
return false;
});
});
</script>
GetAjax.php
<?php
$mysqli = new mysqli("localhost", "root", "", "2015");
if(isset($_POST['try1']))
{
$try1 = $_POST['try1'];
$sql = $mysqli->query("select item_code from code where item='$try1'");
while($row1 = $sql->fetch_assoc())
{
$code = $row1['item_code'];
}
echo $code;
}
?>
使用val()
作为输入元素。
$('#try2').val(data);
for writting a data into input box
you need to use val()
like this
$('#try2').val(data);
html()
is generally used for writting html contents
into divs ,spans , etc
.
Additional Info : for writting data into a label
you can use text("data")
将数据分配给值 。
$('#try2').value =data;
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