why does'nt my js code reflect the right runtime value?

Question

When I run this code (under a <script> code)

window.msg = { a: 0}
var b = window.msg;

function g()
{
    console.log(b)
}
msg = {  a: 1};
g()

in the console - I get {a: 0} .

why is that ? I thought that msg = { a: 1}; will update the reference...

Answer 1

If you change your code to:

window.msg = { a: 0}
var b = window.msg;

function g()
{
    console.log(b)
}
msg.a = 1; // this line is changed
g()

You will get {a:1} .

You're reassigning msg so b just points to the old value of msg .

b does not reference window.msg but the {a:0} object.

Answer 2

You're are creating the object { a: 0 } , and assigning a reference to that object to msg and b . Later, you're creating a new object { a: 1 } , and assigning a reference to that object to msg , but b is still referencing the original object:

window.msg = { a: 0} // msg --> { a: 0 }, b --> undefined
var b = window.msg;  // msg --> { a: 0 }, b --> { a: 0 }

msg = { a: 1};       // msg --> { a: 1 }, b --> { a: 0 }
g()                  // prints b --> { a: 0 }