Php: How to do a var_dump() in the syslog()?

Question

I'm debugging some php code of an API, and for this I'm using syslog() to view my debug messages. The problem is that I want to get some usefull logs. For example, is something null or false? Normally I use var_dump() for this, but since I'm working with in an API, var_dump, f*%$s up the API output.

I tried doing syslog(LOG_ERR, var_dump($myVar)); , but to no avail.

Does anybody know how I can "pretty print" variables/arrays in the syslog?

Answer 1

var_dump() does direct output. There's no provision for it to RETURN its formatted output, so you'll need to use output buffering:

ob_start();
var_dump($something);
syslog(LOG_ERROR, ob_get_clean());

Note that print_r() does have an optional 2nd argument to force it to return instead of outputting:

syslog(LOG_ERROR, print_r($something, TRUE));

Answer 2

var_export()和print_r()可能会返回内容，而不是将其回显

Answer 3

If you are using the syslog primarily as a means to debug, instead of using var_dump , why dont you just 'tail' the syslog by using

tail -f /var/log/syslog

You can grep for any keyword by using

tail -f /var/log/syslog | grep MY_KEYWORD --line-buffered