Allocating memory for array of structs

Question

I've a struct like the one who follows:

typedef struct author
{
char letter;
char *name[200];
int counter;
} Aut, *i_aut;

It consists of a char, and array of "Strings" and int. My goal is to allocate space in memory for an array of 30 of this kind of structs, therefore I tried something like the following:

i_aut lista_autores=calloc(30,sizeof(Aut));

However, it always returns "segmentation fault". I tried to initialize one at a time too, but with the same result. My question is, how do I allocate memory of this kind and how can I access it later?

Thank you in advance, and sorry for any typo.

Answer 1

the struct member name is an array of 200 pointers.
You may want to assign the result of malloc to elements of the array.

struct author *i_aut;
i_aut = malloc(sizeof *i_aut);
if (i_aut) {
    for (size_t k = 0; k < 200; k++) {
        i_aut->name[k] = malloc(30);
        if (!i_aut->name[k]) /* error */;
        /* DONT FORGET TO FREE EACH NAME LATER ON */
    }
    free(i_aut);
}

Answer 2

try using this

    struct author **i_aut;
    i_aut=(struct author **)malloc(30*sizeof(struct author*));
    for(i=0;i<30;i++)
        i_aut[i]=(struct *)malloc(sizeof(struct author)); 

after this you need not allocate space for name[] seperately. you have array of 30 elements of type struct author* and you can access all three type using i_aut[i]->letter; i_aut[i]->name[j]; i_aut[i]->counter; here i<30