Trouble with displaying products on a php page

Question

I am creating an e-commerce website and making an ordering system however, with my code shown below, I get the error "data to render this page is missing". I have tried various work arounds but do not seam to get any further with this.

Could you please see if I am missing anything out or if there is a solution to this question?

At this stage I am trying to display my products from the sql database

Thank You for the help

 <?php 
// Script Error Reporting
error_reporting(E_ALL);
ini_set('display_errors', '1');
?>
<?php 
// Check to see the URL variable is set and that it exists in the database
if (isset($_GET['clothing_name'])) {
 // Connect to the MySQL database  
    include "/xampp/htdocs/website/connection.php"; 

 $sql = mysql_query("SELECT * FROM items WHERE clothing_name='$clothing_name' LIMIT 1");
 $productCount = mysql_num_rows($sql); // count the output amount
    if ($productCount > 0) {
  // get all the clothing details
  while($row = mysql_fetch_array($sql)){ 
    $clothing_name = $row["clothing_name"];
    $size = $row["size"];
    $price = $row["price"];
    $details = $row["details"];

         }

 } else {
  echo "That item does not exist.";
     exit();
 }

} else {
 echo "Data to render this page is missing.";
 exit();
}
mysql_close();
?>

Answer 1

Add this to your code:

$clothing_name = $_GET['clothing_name'];

Update:

 <?php 
 // Script Error Reporting
 error_reporting(E_ALL);
 ini_set('display_errors', '1');

 // Check to see the URL variable is set and that it exists in the database
 if (isset($_GET['clothing_name'])) {
 // Connect to the MySQL database  
 include "/xampp/htdocs/website/connection.php"; 
 $clothing_name = $_GET['clothing_name']; //HERE
 $sql = mysql_query("SELECT * FROM items WHERE clothing_name='".$clothing_name."' LIMIT 1");
 $productCount = mysql_num_rows($sql); // count the output amount
 if ($productCount > 0) {
  // get all the clothing details
  while($row = mysql_fetch_array($sql)){ 
   $clothing_name = $row["clothing_name"];
   $size = $row["size"];
   $price = $row["price"];
   $details = $row["details"];

     }

   } else {
 echo "That item does not exist.";
 exit();
 }

} else {
echo "Data to render this page is missing.";
exit();
}
mysql_close();
?>

Answer 2

First of all you need to pass a QueryString against which there are any records in your database. $_GET[clothing_name] will be set only if you provide it in your QueryString, since you are testing if $_GET[clothing_name] is set by method isset() so if you do not provide it in querystring condition will be false and you'll fall down to else condition.

Secondly define variable $clothing_name as you used it in your query before executing your SQLQuery.

$clothing_name = $_GET['clothing_name'];