I tried compiling some C++ code with VS2013, and unique_ptr::reset()
doesn't seem to work with make_unique()
; a small compilable repro code snippet follows:
#include <memory>
using namespace std;
int main() {
unique_ptr<int[]> p = make_unique<int[]>(3);
p.reset(make_unique<int[]>(10));
}
Compiling from command-line:
C:\\Temp\\CppTests>cl /EHsc /W4 /nologo test.cpp
These are the errors from the MSVC compiler:
test.cpp(6) : error C2280: 'void std::unique_ptr<int [],std::default_delete<_Ty> >::reset<std::unique_ptr<_Ty,std::default_delete<_Ty>>>(_Ptr2)' : attempting to reference a deleted function with [ _Ty=int [] , _Ptr2=std::unique_ptr<int [],std::default_delete<int []>> ] C:\\Program Files (x86)\\Microsoft Visual Studio 12.0\\VC\\INCLUDE\\memory(16 23) : see declaration of 'std::unique_ptr<int [],std::default_delete<_Ty>>::rese t' with [ _Ty=int [] ]
However, the following code seems to compile fine:
p = make_unique<int[]>(10);
What is the reason of this behavior? Why does unique_ptr::operator=()
work with make_unique()
, but unique_ptr::reset()
doesn't?
reset()
takes a pointer.
What you seem to want is simple move assignment :
#include <memory>
using namespace std;
int main() {
unique_ptr<int[]> p = make_unique<int[]>(3);
p = make_unique<int[]>(10);
}
some compilers might still like you to specify the std::move()
there, but it's not strictly required.
Because std::unique_ptr::reset
expects a pointer to an object to be managed, not another unique_ptr
. make_unique
creates a unique_ptr
.
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