I haven´t been able to find this anywhere (mainly because i don´t know what to search for), but when i was reading on W3Schools i stumbled upon the following piece of code:
$sql="SELECT Lastname,Age FROM Persons ORDER BY Lastname";
if ($result=mysqli_query($con,$sql))
{
// Return the number of rows in result set
$rowcount=mysqli_num_rows($result);
printf("Result set has %d rows.\n",$rowcount);
// Free result set
mysqli_free_result($result);
}
Then i wondered the $result, what is that? where does it come from?
When i search for "$result mysqli" nothing helpful really appears...
I´m used to $ being the sign for variables, but this clearly ain´t defined anywhere in the code. Is it some way of calling a function?
The phrase mysqli_query($con,$sql)
is a function call. The tip-off that this is a function call is the parentheses following the function name.
When the code hits that phrase it calls some other PHP code called mysqli_query
(which is in a library somewhere). That code receives from your program two values (the $con and $sql values, performs some actions and returns a newly-created value (an object containing information about and results of your query).
That value is then assigned to the variable $result.
This variable is a PHP object, and it contains the result of a sql query. Thanks to this you can extract data from a data base
The variable is assigned right here:
if ($result=mysqli_query($con,$sql))
You may be more used to this construct:
if ($foo == $bar)
That's a comparison (double equal sign ==
).
However, assignments can happen perfectly well inside an if
statement as well. The assignment expression will return the assigned value as a result which is then used for if
. So:
if ($foo = bar())
is equivalent to
$foo = bar();
if ($foo)
$result is an array which got values from the mysqli_query.
Php's mysqli extension functions are used to run queries with the database. You need configure a connection before running any queries.
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