I have two mysql tables: invoices and payments. I would like to list all invoicerows for a certain period AND a note on if it is paid or not..
SELECT invoices.i_id, invoices.sum, IF EXISTS (Select * from payments WHERE payments.i_id = invoices.i_id) THEN 'PAID' ELSE 'NOT PAID')
FROM invoices
WHERE invoices.date >= 2014-01-01
AND invoices.date <= 2014-01-31
RESULTING:
1252515 122,50 PAID
1252514 150,40 PAID
1257425 1180,40 NOT PAID
and so on... Does not work. Can this be done in a (mysql) query?
You can use JOIN
with CASE
SELECT i.i_id, i.`sum`,
(CASE WHEN p.i_id IS NOT NULL THEN 'PAID' ELSE 'NOT PAID' END) `status`
FROM invoices i
LEFT JOIN payments p ON(p.i_id = i.i_id)
WHERE i.date >= 2014-01-01
AND i.date <= 2014-01-31
Another way you can also use IF
SELECT i.i_id, i.`sum`,
IF(p.i_id IS NULL, 'NOT PAID', 'PAID') `status`
FROM invoices i
LEFT JOIN payments p ON(p.i_id = i.i_id)
WHERE i.date >= 2014-01-01
AND i.date <= 2014-01-31
Try using CASE instead of IF.:
CASE WHEN EXISTS (Select * from payments WHERE payments.i_id = invoices.i_id) THEN 'PAID' ELSE 'NOT PAID' END
Simple example (fiddle) :
CREATE TABLE tbl1 (id INT);
CREATE TABLE tbl2 (id INT);
INSERT INTO tbl1 VALUES (1),(2);
INSERT INTO tbl2 VALUES (1);
SELECT id
,CASE WHEN EXISTS (SELECT * FROM tbl2 WHERE tbl2.id = tbl1.id) THEN 'PAID' ELSE 'NOT PAID' END
FROM tbl1
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.