I have a question about some trying to wrap around a sequence of numbers that I'm trying to shift in the C programming language. The first value that is found in the sequence of numbers I calculate via a loop gets thrown out in the end. Here is what the code looks like right now:
numbers[d] = numbers[x];
for (d = y-1; d >=0; d --){
numbers[d] = numbers[(d - 1) % y];
printf(" numbers[d] = %d \n", numbers[d]);
}
Here are the numbers[x] I calculated from my previous loop:
1, 17, 3, 15, 14, 6, 12, 8, 10
Here is what the numbers[d] currently looks like:
17, 3, 15, 14, 6, 12, 8, 10, 10
...and here is what it should look like:
17, 3, 15, 14, 6, 12, 8, 10, 1
It seems like it doesn't wrap the 1 around to the end. Is there a conditional that I am missing in my loop? Thanks!
#include <stdio.h>
static const int debug = 0;
static void dump_array(const char *tag, int n, const int array[n])
{
printf("%s (%d)", tag, n);
for (int i = 0; i < n; i++)
printf("%3d", array[i]);
putchar('\n');
}
static void rot1u(int n, int numbers[n])
{
int v = numbers[n-1];
for (int d = n - 1; d >= 0; d--)
{
numbers[d] = numbers[(n + d - 1) % n];
if (debug)
printf(" numbers[%d] = %d\n", d, numbers[d]);
}
numbers[0] = v;
dump_array("Up After: ", n, numbers);
}
static void rot1d(int n, int numbers[n])
{
int v = numbers[0];
for (int d = 0; d < n; d++)
{
numbers[d] = numbers[(d + 1) % n];
if (debug)
printf(" numbers[%d] = %d\n", d, numbers[d]);
}
numbers[n-1] = v;
dump_array("Dn After: ", n, numbers);
}
int main(void)
{
int numbers[] = { 1, 17, 3, 15, 14, 6, 12, 8, 10 };
enum { N_NUMBERS = sizeof(numbers) / sizeof(numbers[0]) };
dump_array("-- Before:", N_NUMBERS, numbers);
rot1u(N_NUMBERS, numbers);
rot1d(N_NUMBERS, numbers);
rot1d(N_NUMBERS, numbers);
rot1d(N_NUMBERS, numbers);
rot1u(N_NUMBERS, numbers);
rot1u(N_NUMBERS, numbers);
return 0;
}
-- Before: (9) 1 17 3 15 14 6 12 8 10
Up After: (9) 10 1 17 3 15 14 6 12 8
Dn After: (9) 1 17 3 15 14 6 12 8 10
Dn After: (9) 17 3 15 14 6 12 8 10 1
Dn After: (9) 3 15 14 6 12 8 10 1 17
Up After: (9) 17 3 15 14 6 12 8 10 1
Up After: (9) 1 17 3 15 14 6 12 8 10
Let's analyze your for
loop, minus the printf
statement.
for (d = y-1; d >=0; d --){
numbers[d] = numbers[(d - 1) % y];
}
Before you start the loop, you have the following values in numbers
.
1, 17, 3, 15, 14, 6, 12, 8, 10
The value of y
is 9
.
In the first iteration of the loop, d = 8
. (d-1)%y = 7
. You replace the value of number[8]
by number[7]
. The array becomes:
1, 17, 3, 15, 14, 6, 12, 8, 8
In the next iteration of the loop, d = 7
. (d-1)%y = 6
. You replace the value of number[7]
by number[6]
. The array becomes:
1, 17, 3, 15, 14, 6, 12, 12, 8
When you reach the iteration where d=1
, (d-1)%y = 0
. You replace the value of number[1]
by number[0]
. The array becomes:
1, 1, 17, 3, 15, 14, 6, 12, 8
In the next iteration, d=0
, (d-1)%y = -1
. The statement
numbers[d] = numbers[(d - 1) % y];
is equivalent to
numbers[0] = numbers[-1];
This certainly leads to undefined behavior but it doesn't explain the other numbers in your output. Maybe the output that you posted corresponds to a different block of code.
I think the answer by @JonathanLeffler gives a solution to your algorithmic problem. I won't repeat that here.
您需要保存在循环之前应该旋转到另一侧的元素,然后才将其放入适当的位置(将它们放入适当的位置)。
#include <stdio.h>
#include <time.h>
#define METHOD 2
#define MAX_SKIERS 20
int starting_lineup[MAX_SKIERS+1];
int main(void)
{
int i, num_skiers = 20;
srand(time(NULL));
int pos1, pos2, temp;
for (i = 0; i <= num_skiers; i++)
starting_lineup[i] = i;
for (i = 0; i < num_skiers*2; i++) {
// Generate two random positions
pos1 = rand() % num_skiers + 1;
pos2 = rand() % num_skiers + 1;
// Swap the skiers at the two positions
temp = starting_lineup[pos1];
starting_lineup[pos1] = starting_lineup[pos2];
starting_lineup[pos2] = temp;
}
printf("The starting lineup (first to last):\n");
for (i = 1; i <= num_skiers; i++)
printf("%s%d", (i == 1 ? "" : ", "), starting_lineup[i]);
putchar('\n');
return 0;
}
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