Show 3 top results according to date using sql

Question

I have a website , and I created a book library in it.

The table is: book

It contain: book_id , book_title , book_cat , book_img , book_content , active , book_date , visits , book_sender )

The 'book_sender' is the ID of the sender because any logged in user can add books , I wanted to make a gift each week to the best sender (who sent alot of books) so I wanted to show top 3 sender's of the week in a PHP file to make challenge between the top3.

Champ
----------
book_id
book_title
book_cat
book_img
book_content
active
book_date
visits
book_sender

Answer 1

the sql query goes like this:

select book_sender, count(book_id) as num_books 
from champ 
where DATEDIFF(sysdate(), book_date) <= 7 
group by book_sender
limit 0, 3;

Answer 2

Code snippet (replace db_name, db_user, and db_password with appropriate values):

<?php
   $db = new PDO('mysql:host=localhost;dbname=db_name;charset=UTF8', 'db_user', 'db_password');
   $db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
   $db->setAttribute(PDO::ATTR_EMULATE_PREPARES, false);
   $stm = $db->prepare( "
      SELECT book_sender `Sender ID`, COUNT(*) `Books Sent`
      FROM Champ
      WHERE book_date > DATE_ADD( now(), INTERVAL -7 DAY )
      GROUP BY book_sender
      LIMIT 0, 3" );
    $stm->execute();
    while( $row = $stm->fetch(PDO::FETCH_ASSOC) ) {
       $result[] = $row;
    }

    // Step through $result and print out

?>

Also assuming you're using MySQL and PDO.