I'm trying to create an "editable" drop down list. I have a drop down list populated from a table "city" in my db, it works perfect but now I want user to be able to add a new value to the list if it doesn't exist there (and I want to save this value, so next time it appears in the drop down list). Any ideas? Thank you
<select name="city">
<?php
// connecting to DB
$con= mysqli_connect('localhost','root','1234','e-sage');
// enable hebrew input
mysqli_set_charset($con,'utf8');
// read the city table from DB
$sql = mysqli_query($con,"SELECT CityName FROM city");
while ($row = mysqli_fetch_array($sql)){
// creating temporary variable for each row
$city1=$row["CityName"];
//assigning a value to each option in dropdown list
echo "<option value=\"$city1\"> $city1 </option>";
}
?>
</select>
You can provide a 'other' selection in the dropdown. If user selects that then display a new textbox from which you can insert in the database.
use datalist tag
Then try this: Lets agree that you already got all the cities in array OK?
<select name="city">
<?PHP
foreach($cities as $city)
{
echo '<option value="'.$city.'">'.$city.'</option>';
}
?>
</select>
<form method="post">
<label for="new_city">New city</label>
<input id="new_city" name="new_city" placeholder="Enter new city name" />
<input type="button" id="addCity" value="Insert city" />
</form>
<script>
$(document).on('click','#addCity',function()
{
var new_city=$("#new_city").val();
var e=0;
$("[name='city'] option").each(function(i,item)
{
var check_city=$(item).val();
if(check_city==new_city)
{
e++;
}
else
{
}
});
if(e>0)
{
alert('The same');
}
else
{
/*Submit the form*/
alert('This city is fresh and new');
}
});
</script>
So the script is checking if the value is already assigned to option. If not - allows to submit the form.
Check this one: http://jsfiddle.net/n47N2/1/
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