I'm currently using the simple XML library, and the tutorial didn't have a runnable example for ElementLists. http://simple.sourceforge.net/home.php
I have an example class:
@Root
public class Example {
@ElementList
private List<String> text;
@Attribute
private int index;
public Example() {
super();
}
public Example(List<String> text, int index) {
this.text = text;
this.index = index;
}
public List<String> getMessage() {
return text;
}
public int getId() {
return index;
}
}
And a simple class for running:
public class M {
public static void main(String[] args) throws Exception {
Serializer serializer = new Persister();
List<String> l = new LinkedList<String>();
l.add("f");
l.add("f");
Example example = new Example(l, 123);
File result = new File("example.xml");
serializer.write(example, result);
}
}
The XML that I generate is:
<example index="123">
<text class="java.util.LinkedList">
<string>f</string>
<string>f</string>
</text>
</example>
Why am I getting the class="java.util.LinkedList"? I'm confused on how remove this attribute.
You can use the VisitorStrategy to intercept the serialization of the object.
Strategy strategy = new VisitorStrategy(new Visitor() {
@Override
public void write(Type type, NodeMap<OutputNode> node) throws Exception {
if ("text".equals(node.getName())){
node.remove("class");
}
}
...
});
I was working on the same problem and I got a way to avoid the 'class' attribute.
Instead of using @ElementList like this:
@ElementList(name="Files", entry="File")
You can use @Path annotation with the @ElementList as follows:
@Path(value="Files")
@ElementList(inline=true, entry="File")
You can use an Implementation for an @ElementList List, example:
LinkedList instead of List.
@ElementList
private LinkedList<String> texts;
This will avoid class attribute not wanted.
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