named urls of the form {%url 'somenamedurl' %} in django not working

Question

That named url worked before, i put another django project and installed few packages like pyjasper etc. My bad I didnt do virtualenv.

Now the other project is not important. Current version of django I am using is 1.6.2. I am not able to trace the error.

It says error rendering

SyntaxError at /dashboard/
invalid syntax (views.py, line 7)

Error during template rendering In template D:\\djangoprojects\\prmanager\\templates\\menu.html, error at line 3

1   {% load static %}
2   <li class="active">
3       <a href="{% url 'dashboard' %}">
4           <i class="fa fa-dashboard"></i> <span>Dashboard</span>
5       </a>
6   </li>
7   
8   <li class="treeview">
9       <a href="#">
10          <i class="fa fa-folder"></i> <span>Work Orders</span>
11          <i class="fa fa-angle-left pull-right"></i>
12      </a>
13      <ul class="treeview-menu">

Notice line number 3. I tried named them with quotes and without.

Not able to find which views.py its talking about. Because in the dashboard app, there is no line no 7 in views.py

Can somebody throw some light as to where to look for the bug. If this info is not sufficient, please let me know and I will post the same.

What I do know is, what was working before, stopped working.

Edit urls.py

urlpatterns = patterns('',
    # Examples:
    # url(r'^$', 'prmanager.views.home', name='home'),
    # url(r'^blog/', include('blog.urls')),

    url(r'^dashboard/', include('dashboard.urls')),

    url(r'^materials/', include('materials.urls')),
    url(r'^suppliers/', include('suppliers.urls')),
    url(r'^purchaserequest/', include('purchaserequest.urls')),
    url(r'^purchaseorder/', include('purchaseorder.urls'), name="purchaseorder"),
    url(r'^admin/', include(admin.site.urls)),

    url(r'^getSuppliersJson/', 'commontools.tools.getSuppliersJson', name="getSuppliersJson"),
    url(r'^getPOJson/', 'commontools.tools.getPOJson', name="getPOJson"),


) + static(settings.STATIC_URL, document_root=settings.STATIC_ROOT)

Dashboard app's urls.py

from django.conf.urls import patterns, url

urlpatterns = patterns('dashboard.views',   
    url(r'^$', 'dashboard', name="dashboard"),
    #url(r'^newpurchaserequest/', 'newpurchaserequest', name="newpurchaserequest"),
)

Answer 1

You are already placing the error,

SyntaxError at /dashboard/
invalid syntax (views.py, line 7)

So problem is in your views.py file at line 7.

Update:

you are included dashboard urls.py, but at the same time you used $ . It is not matching next sub patterns.

yes now problem is here url(r'^dashboard/$', include('dashboard.urls')), use this url(r'^dashboard/', include('dashboard.urls')),

app configuration is like this,

In root urls.py:

urlpatterns = patterns('',

    url(r'^dashboard/', include('dashboard.urls')),
)

In dashboard app:

In urls.py:

urlpatterns = patterns('dashboard.views',   
    url(r'^$', 'dashboard', name="dashboard"),
)

In views.py:

def dashboard(request):
    context = {}
    return render(request, 'dashboard/dashboard.html', context)

Answer 2

You should be using this syntax:

{% url 'dashboard' as dashboard_url %}
<a href="{{ dashboard_url }}">Link</a>