xxxI am trying to insert data in mysql database from my Android app using php file. I don´t know what I am doing wrong, here is my android code:
public void insert()
{
ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
nameValuePairs.add(new BasicNameValuePair("nick",nick));
nameValuePairs.add(new BasicNameValuePair("minuto",minuto));
nameValuePairs.add(new BasicNameValuePair("id_pelicula",String.valueOf(id_pelicula)));
try
{
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://xxxx.xxxxx.com/xxxx/insertar.php");
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
is = entity.getContent();
Log.e("pass 1", "connection success ");
}
catch(Exception e)
{
Log.e("Fail 1", e.toString());
Toast.makeText(getApplicationContext(), "Invalid IP Address",
Toast.LENGTH_LONG).show();
}
try
{
BufferedReader reader = new BufferedReader
(new InputStreamReader(is,"iso-8859-1"),8);
StringBuilder sb = new StringBuilder();
while ((line = reader.readLine()) != null)
{
sb.append(line + "\n");
}
is.close();
result = sb.toString();
Log.e("pass 2", "connection success ");
}
catch(Exception e)
{
Log.e("Fail 2", e.toString());
}
try
{
JSONObject json_data = new JSONObject(result);
code=(json_data.getInt("code"));
if(code==1)
{
Toast.makeText(getBaseContext(), "Opinión enviada correctamente",
Toast.LENGTH_SHORT).show();
}
else
{
Toast.makeText(getBaseContext(), "Disculpe, inténtelo de nuevo",
Toast.LENGTH_LONG).show();
}
}
catch(Exception e)
{
Log.e("Fail 3", e.toString());
}
}
and here is my php file code:
<?php
// Connection data
$host = 'xxx.xxx.com';;
$uname = 'uxxxx';
$pwd = 'xxxxx';
$db = 'xxxxx';
$con = mysql_connect($host,$uname,$pwd) or die("connection failed");
mysql_select_db($db,$con) or die("db selection failed");
$nick=$_REQUEST['nick'];
$minuto=$_REQUEST['minuto'];
$id_pelicula=$_REQUEST['id_pelicula'];
$flag['code']=0;
if($r=mysql_query("insert into opiniones values('$nick','$minuto','$id_pelicula') ",$con))
{
$flag['code']=1;
echo"hi";
}
print(json_encode($flag));
mysql_close($con);
?>
Perhaps is because in my mysql database the "minuto" variable is integer and I use like String from android? Please somebody can help me? Thank you so much
我已解决,这句话的php文件中有一个错误:
if($r=mysql_query("insert into opiniones (nick, minuto, id_pelicula) values('$nick','$minuto','$id_pelicula') ",$con))
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