I've been trying to do this for the last two days. I read a lot of tutorials and I learned a lot of new things but so far I couldn't manage to achieve what I'm trying to do. Let's say this is the command line output:
Johnny123 US 224
Johnny123 US 145
Johnny123 US 555
Johnny123 US 344
Robert UK 4322
Robert UK 52
Lucas FR 344
Lucas FR 222
Lucas FR 8945
I want to print the lines which match 'the first field (Lucas) of last line'.
So, I want to print out:
Lucas FR 344
Lucas FR 222
Lucas FR 8945
Notes:
Here is another way using tac
and awk
:
tac file | awk 'NR==1{last=$1}$1==last' | tac
Lucas FR 344
Lucas FR 222
Lucas FR 8945
The last tac
is only needed if the order is important.
awk 'NR==FNR{key=$1;next} $1==key' file file
或者如果你愿意的话
awk '{val[$1]=val[$1] $0 RS; key=$1} END{printf "%s", val[key]}' file
This might work for you (GNU sed):
sed -nr 'H;g;/^(\S+\s).*\n\1[^\n]*$/!{s/.*\n//;h};$p' file
Store lines with duplicate keys in the hold space. At change of key remove previous lines. At end-of-file print out what remains.
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