I have the following table structure: Value
(stores random integer values), Datetime` (stores purchased orders datetimes).
How would I get the average value from all Value
rows across a full day?
I'm assuming the query would be something like the following
SELECT count(*) / 1
FROM mytable
WHERE DateTime = date(now(), -1 DAY)
You can GROUP BY
the DATE
part of DATETIME
and use AVG
aggregate function to find an average value for each group :
SELECT AVG(`Value`)
, DATE(`Datetime`)
FROM `mytable`
GROUP BY DATE(`Datetime`)
Looks like a simple AVG
task:
SELECT `datetime`,AVG(`Value`) as AvgValue
FROM TableName
GROUP BY `datetime`
To find average of a specific day:
SELECT `datetime`,AVG(`Value`) as AvgValue
FROM TableName
WHERE `datetime`=@MyDate
GROUP BY `datetime`
Or Simply:
SELECT AVG(`Value`) as AvgValue
FROM TableName
WHERE `datetime`=@MyDate
Explanation:
AVG
is an aggregate function used to find the average of a column. Read more here .
尝试一下它的工作...
Select AVG(value),convert(nvarchar,DateTime,103) from table group by convert(nvarchar,DateTime,103)
The following query will give you what u want..
SELECT DATE_FORMAT(thedate_field, '%Y-%m-%d') as theday, avg (value)
FROM mytable group by
DATE_FORMAT(thedate_field, '%Y-%m-%d')
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