In reference to Check if no result found in mysql db
It was previously thought that you could check to see if there as a record set returned by doing the following;
$result= mysqli_query($conn,$sql);
$rowCount = mysqli_num_rows($result);
In the question about this was the accepted solution. While this may work fine, in the version of PHP which I'm using [PHP 5.5.12-2+deb.sury.org~precise+1] using this type of check puts an entry in my error-log
PHP Warning: mysqli_num_rows() expects parameter 1 to be mysqli_result,
boolean given in /var/www/scripts/common_php.php on line 20
I am trying to be hyper vigilant in my code so that there are NO entries produced in my error log other than 404 errors. I am trying to code to the strictest standard. So my question remains, how do you properly determine if the record set that comes back from a query is empty or not?
Is it as simple as
if (!result) {
// didn't work, do something else
} else {
// records set returned, resume normal processing of query result here
//enter code here
}
** Sorry corrected the query and num_rows check lines.
It doesn't look like you got zero results - it looks like your query failed (and therefore didn't return a mysqli_result).
EDIT: To answer your question more specifically, yes it is as simple as
if($result)
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