list inspect second item print first item in list

Question

I'm trying to dissect items from a list (from a file)

file data with name, number of goals, passes.
Luis,8,3
Montes and Kyle,10,8
Sharon, 22, 4
Nayum,3,8

So far:

filen=open("WorldData.txt", 'r')

values = []##List
for line in open(filen):
    values.append(line.rstrip('\n').split(','))

xl=values

numlist=[]
for line in xl:
    numlist.append(int(line[1]))#second element which are goals

x=(max(numlist))
print(x)

filen.close()

Which would give out: 22 but I'm also trying to find the name of the person who won. I tried indexing so I could find the number of the line where the value is [::] so I could then print the first element...

print(xl.index(str(x))) 

but it says

ValueError: '22' is not in the list

So I can't even get there.

How can I find who made the most goals?

Answer 1

Here is how I would read the csv data:

import csv

data={}
with open(fn, 'r') as fin:
    reader=csv.reader(fin)
    header=next(reader)
    for row in reader:
        data[row[0]]=list(map(int, row[1:]))
print(data)
# {'Luis': [8, 3], 'Nayum': [3, 8], 'Montes and Kyle': [10, 8], 'Sharon': [22, 4]}

You can see now that you have a dict of lists

Now just find the entry that has the max value for the value number of goals which is the first element in each list. You can use the built-in max with a key function to see who won:

print(max(data.items(), key=lambda t: t[1][0]))
# ('Sharon', [22, 4])

Answer 2

use numlist as dictionary. . so the code would be something like

goals = 0

numlist={}
for line in xl:
    numlist[line[0]]=int(line[1])#second element witch are goals

for player in numlist:
    if numlist[player] > goals:
        winner = player
        goals = numlist[player]
print goals, winner

answer printed would be 22 Sharon. would have take care of duplicates though or tie amongst multiple winner. for that you can maintain a list for winner and append it .