PHP create a hierarchy menu structure

Question

Basically I have a table in MYSQL

Name    ID     Parent  
Bob     321    root  
Sue     32     root  
Boo     393    32  
Geek    72     393  
Sam     312    393  
Tovoc   341    321  
Reese   322    393  
Sheep   811    341  

I want to create a menu that outputs a menu structure with submenus based on the parent ID

So it should output

Bob  
 Tovoc 
  Sheep

Sue
 Boo
 Sam
  Geek
 Reese

The child entries are linked with the parent ID and if they have a parent they become a child. Ultimately it would build a multidimentual array. Clues?

Heres what I got so far. It works, but I can't figure out how to increase or reset the margin style properly to get a nice structure view. I have the margin-left increase by 10px in every child elements found, then reset back to 1 if the parent is user

isparent(user,1);

  function isparent($Parent,$if=1){

  $stdr = 'SELECT * FROM CraveBins WHERE UserID = '.$_SESSION[CraveUserID].' AND Parent=\''.$Parent.'\' ORDER BY Name ASC';
 $resultMainMenu = mysql_query($stdr) or die('421 '.$stdr.mysql_error());
 if(mysql_num_rows($resultMainMenu)){
 while($row = mysql_fetch_array($resultMainMenu)){
 $if++; 
 echo '<div class="binDir" onclick="setBin(this)" id="BinListUser" style="margin-left:'.(5+($if * 10)).'px" driID="'.$row[ID].'">'.$row['Name'].'</div>'; // echo main menu
 $n =  isparent($row['ID'],$if);
}//end while 
}else{
$if=1;
} // if rows        
}//end function

Answer 1

I don't understand your $if++ . I thought this was your level of indentation. If so: remove the $if++ , modify the inner isparent($row['ID'],$if+1) and you should be fine ... I guess.

Alternatively, move your $if++ outside the while loop (before ;o)

Also: you don't need mysql_num_rows(...) , I believe. Just start fetching, and it'll return nothing if it's finished. Also, don't use mysql_*, use mysqli or pdo.

If your $if was meant to count the children, just call it $n , don't mix depth and count.