Unable to remove html content using JQUERY
Question
I am unable to remove the div with ID "Third" and display the result content in div with ID "Fourth" . Please Note :- I need to append #Third content to #Fourth and then remove at later stage.
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title></title>
<script src="../jquery-ui-1.10.4.custom/js/jquery-1.10.2.js" type="text/javascript"></script>
<script src="../jquery-ui-1.10.4.custom/js/jquery-ui-1.10.4.custom.min.js" type="text/javascript"></script>
<link href="../jquery-ui-1.10.4.custom/css/ui-lightness/jquery-ui-1.10.4.custom.min.css"
rel="stylesheet" type="text/css" />
<script type="text/javascript">
$(function() {
var widget = {}
$("#Vshowdialog").click(function() {
widget.doInitialize();
});
widget.doInitialize = function() {
$("#Fourth").append($("#First").html());
$("#Fourth").append($("#Second").html());
$("#Fourth").append($("#Third").html());
widget.showLightBox();
};
widget.showLightBox = function() {
text = $('#Fourth').html();
$(text).find("#Third").remove();
$("#Fourth").dialog();
};
});
</script>
</head>
<body>
<input type="button" id="Vshowdialog" value="ShowDialog" />
<div id="First">
<div id="content">
This is my main Firstcontent.</div>
<div id="sidebar">
This is a FirstSideBar</div>
</div>
<div id="Second">
<div id="secondOne">
This is my main Second content.</div>
<div id="secondTwo">
This is a second sidebar</div>
</div>
<div id="Third">
hello
<div id="thirdOne">
This is my main third content.</div>
<div id="thirdTwo">
This is a third sidebar</div>
</div>
<div id="Fourth">
</div>
</body>
</html>
5 answers
solution1
1 2014-06-26 11:32:42
You can use:
$('#Fourth').append($('#third'));
$('#thirdOne').unwrap();
or
$('#Fourth').append($('#Third')).find('#thirdOne').unwrap();
solution2
1 2014-06-26 11:44:33
$(function() {
var widget = {}
$("#Vshowdialog").click(function() {
widget.doInitialize();
});
widget.doInitialize = function() {
$("#Fourth").append($("#First").html());
$("#Fourth").append($("#Second").html());
$("#Fourth").append($("#Third").html());
widget.showLightBox();
};
widget.showLightBox = function() {
$('#Fourth').find("#thirdOne").remove();
$('#Fourth').find("#thirdTwo").remove();
$("#Fourth").dialog();
};
});
Try this it will work fine.
solution3
0 2014-06-26 11:39:47
You're appending the "inner html" of the other elements to #Fourth ; to keep the identifiers intact you should do this:
$('#First,#Second,#Third').appendTo('#Fourth');
Then, at a later stage you can simply remove #Third :
$('#Third').remove();
solution4
0 2014-06-26 11:49:22
you'll want to initialize this variable
text = $('#Fourth').html();
But your looking for #Third within #Fourth when you only included the inner html, specificly
var text = $('#Fourth').html(); //contents of fourth
$(text).find("#Third").remove(); //third was added as inner Html without the wrapping container.
You should be able to just change
$("#Fourth").append($("#Third").html());
to
$("#Fourth").append($("#Third"));
The real question is why are you adding Third to Fourth and then removing it? Your code is equivalent to this, in execution, assuming it was fixed.
$("#Fourth").append($("#Third"));
$("#Fourth").find("#Third").remove();
solution5
0 2014-06-26 12:04:05
//cache the third div content
var tempThird = $('#Third');
//add your result to Fourth div
$('#Fourth').html("resultcontent");
//remove the third div
$('#Third').remove();
//tempThird will still have the essence of #Third div which you can use anywhere.
You can check the remove API documentation on http://api.jquery.com/remove/
Hope this solves your problem.
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