Start a process with a command line parameter of another executable

Question

I'm trying to pass an .exe to another through C# code.

Here's my code so far:

string ex1 = System.Windows.Forms.Application.StartupPath.ToString() + "\\dev\\psm.exe";
string ex2 = System.Windows.Forms.Application.StartupPath.ToString() + "\\dev\\Application\\app.exe";

ProcessStartInfo startInfo = new ProcessStartInfo();
startInfo.CreateNoWindow = false;
startInfo.UseShellExecute = false;
startInfo.FileName = ex1;
startInfo.WindowStyle = ProcessWindowStyle.Normal;
startInfo.Arguments = ex2;

try
{
    Process.Start(startInfo);
}
catch
{
}

Which argument would work as dragging a file onto the application?
Details:
When you run psm.exe normally, it prompts for file name and directory.

However, when you drag an approved app on psm.exe,
it loads the app automatically.

How can this be done with C#?

Answer 1

You can run another app synchronously like this:

System.Diagnostics.Process myapp = new System.Diagnostics.Process();
myapp.StartInfo.FileName = ex1;
myapp.StartInfo.Arguments = ex2;
myapp.Start();
myapp.WaitForExit();

Depending on how the app you want to launch expects the command line arguments to be passed, you may need this for the arguments:

myapp.StartInfo.Arguments = String.Format("/MyArgumentName={0}", ex2);

That would be the equivalent of:

c:\MyApplicationStartupPath\dev\psm.exe /MyArgumentName=c:\MyApplicationStartupPath\Application\App.exe

Be sure to match the way app.exe expects the parameters in your StartInfo.Arguments