Consider below String,
var originalStr = "This is first string JUNKCHARS";
I need a regex to find a pattern " JUNKCHAR", ie characters JUNKCHAR with (any number of) whitespace before it and end of string after it.
e.g,
// case 1
originalStr = "This is first string JUNKCHARS";
replacedStr = originalStr.replace(<pattern>, "");
console.log(replacedStr); // should output - This is first string
// case 2
originalStr = "This is first string JUNKCHARS";
replacedStr = originalStr.replace(<pattern>, "");
console.log(replacedStr); // should output - This is first string
// case 3
originalStr = "This is first string JUNKCHARS ";
replacedStr = originalStr.replace(<pattern>, "");
console.log(replacedStr); // should output - This is first string JUNKCHARS
// case 4
originalStr = "This is first string JUNKCHARS test";
replacedStr = originalStr.replace(<pattern>, "");
console.log(replacedStr); // should output - This is first string JUNKCHARS test
// case 5
originalStr = "This is first stringJUNKCHAR";
replacedStr = originalStr.replace(<pattern>, "");
console.log(replacedStr); // should output - This is first stringJUNKCHAR
// case 6
originalStr = "This is first string JUNKCHARtest";
replacedStr = originalStr.replace(<pattern>, "");
console.log(replacedStr); // should output - This is first string JUNKCHARtest
I have tried several regex but none seems to meet my requirement. Could anyone please help me in finding the right regex. Your help will be appreciated.
You may try something like this:
var text = 'This is first string JUNKCHARS ';
text = text.replace(/\s{2,}JUNKCHARS/g,'').trim();
console.log(text);
Here is a demo: http://jqversion.com/#!/NYBiNrT
You can try something like this:
(?:^|\\s)(JUNKCHARS)(?=\\s|$)|\\sJUNKCHARS\\s
Let's go through that pattern by part
\\s+
JUNKCHARS
$
in regex syntax Together you'll get var pattern = /\\s+JUNKCHARS$/
You can fiddle around with it http://regex101.com/r/sU4eI3/1
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