How can i run ajax on php codeigniter
Question
I'm trying to use javascript code on my codeIgniter project. But I didn't execute it. I tried too many ways for solve it: I called the external js code, it didn't work. I put in my view page it dind't work as well. I think the problem is simple but I can't see it. What do you think about this problem?
view.php
<html>
<?php include("/external/css/style.css"); ?>
<head>
<title>New Customer</title>
<script src="//ajax.googleapis.com/ajax/libs/jquery/2.0.0/jquery.min.js"></script>
<script>
function makeAjaxCall(){
$.ajax({
alert("I'm here"); // I cant see that
type: "post",
url: "http://localhost/codeigniter_2/index.php/homepage/verifyUser",
cache: false,
data: $('#addCust').serialize(),
success: function(json){
try{
var obj = jQuery.parseJSON(json);
alert( obj['STATUS']);
}catch(e) {
alert('Exception while request..');
}
},
error: function(){
alert('Error while request..');
}
});
}
</script>
</head>
<body>
<h1>Customer Add</h1><a href="http://localhost/codeigniter_2/index.php">list</a>
<form name="addCust" method="post" action="insert">
<table border="1">
<tr>
<th>Customer Name:</th>
<td><input type="text" id="custom" name="customerName"/></td>
<tr>
<th>Customer Phone:</th>
<td><input type="text" name="phone"/></td>
<tr>
<th>Address:</th>
<td><input type="text" name="address"/></td>
.
.
.
<tr>
<td><input type="button" onclick="javascript:makeAjaxCall();" value="Submit"></td>
<td><input type="reset"></td>
</tr>
</form>
</table>
</body>
</html>
conroller.php
public function verifyUser()
{
$userName = $_POST['customerID'];
$phone = $_POST['phone'];
$address = $_POST['address'];
if($userName=='' && $phone=11){
$status = array("STATUS"=>"true");
}
echo json_encode ($status) ;
}
What's wrong??
3 answers
solution1
6 2014-07-18 12:08:17
You need to put your code in a document ready handler -
$(document).ready(function() {
// your code here
function makeAjaxCall....
// EDIT: adding the click handler
$('#formSubmit').click(function()....
});
Also, instead of doing this -
<input onclick="javascript:makeAjaxCall();" value="Submit">
I would give the input an id -
<input name="submit" id="formSubmit" value="Submit">
And add a click handler to the JavaScript -
$('#formSumbit').click(function(e) {
e.preventDefault(); // keeps the button from acting normally
makeAjaxCall(); // calls the function
});
One more thing - use console.log() instead of alert() in your code. Alerts are not a good method of troubleshooting because they cause the code to halt until acknowledgement and using them during an AJAX call is especially bad.
solution2
0 2014-07-18 12:08:23
change this
<input type="button" onclick="javascript:makeAjaxCall();" value="Submit">
to
<input type="button" onclick="makeAjaxCall();" value="Submit">
EDITED
$userName = $_POST['customerID'];// check this
$phone = $_POST['phone'];
$address = $_POST['address'];
if($userName=='' && $phone=11){
$status = array("STATUS"=>"true");
}
echo json_encode ($status) ;
also add id to form
<form name="addCust" id="addCust" method="post" action="insert">
solution3
0 2017-03-08 07:22:21
Hello Here you can check the below link and it will useful for you
http://www.ccode4u.com/how-jquery-ajax-works-in-codeigniter.html
Thank you :)
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.