Im getting this error on this code!
esImpar :: Integer -> Bool
esImpar a = if (a mod 2) /= 0 then True
else False
Error: Couldn't match expected type (Integer -> Integer -> Integer) -> (Integer -> Integer) -> Integer -> Integer' with actual type Integer
The function `a' is applied to three arguments,
but its type Integer' has none
In the first argument of (/=), namely (a mod fromIntegral 2)
In the expression: (a mod 2) /= 0
mod
by itself is just a function, not an operator; you can use it as mod a 2
or infix as a `mod` 2
. (Here you are trying to use a
as a function, as the error message says.)
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