I passed coordinates of points into vector, and there are some repeating points, so I want to delete other repeating points and just keep the only points.
for example:
vector<Point2f> points;
points[0]=Point2f(1,1);
points[1]=Point2f(2,3);
points[2]=Point2f(1,1);
points[3]=Point2f(2,3);
points[4]=Point2f(1,1);
points[5]=Point2f(4,1);
I want to get the result like this:
points[0]=Point2f(1,1);
points[1]=Point2f(2,3);
points[2]=Point2f(4,1);
PS The order of elements is unchanged.
What I have tried is show as below:
#include <opencv2/core/core.hpp>
#include <vector>
#include<iostream>
using namespace std;
using namespace cv;
int main()
{
vector<Point2f> pointTemp;
pointTemp[0]=Point2f(1,1);
pointTemp[1]=Point2f(2,3);
pointTemp[2]=Point2f(1,1);
pointTemp[3]=Point2f(2,3);
pointTemp[4]=Point2f(1,1);
pointTemp[5]=Point2f(4,1);
for(vector<Point2f>::iterator it=pointTemp.begin();it!=pointTemp.end();it++)
{
for(vector<Point2f>::iterator it1=it+1;it1!=pointTemp.end();)
{
if(it->x==it1->x&&it->y==it1->y)
{
it1=pointTemp.erase(it1);
}
else
{
it1++;
}
}
}
//cout<<pointTemp.size()<<endl;
return 0;
}
Here's my crack at it. It probably requires that you pass --std=c++11
as a parameter ot g++. Notice that the insertion order of unique elements is maintained. It's also O(N)
for runtime complexity.
// remove_duplicates: removes all duplicated elements from the vector passed in
void remove_duplicates(std::vector<Point2f>& vec)
{
std::unordered_set<Point2f> pointset; // unordered_set is a hash table implementation
auto itor = vec.begin();
while (itor != vec.end())
{
if (pointset.find(*itor) != pointset.end()) // O(1) lookup time for unordered_set
{
itor = vec.erase(itor); // vec.erase returns the next valid iterator
}
else
{
pointset.insert(*itor);
itor++;
}
}
}
The above function, as a result of using unordered_set
, requires a hash function to have been previously declared for Point2f. You can define this however you like. My simple implementation is below.
You'll also likely need to have an ==
operator defined for Point2f as well as appropriate constructors to satisfy the vector and unordered_set semantics.
Complete code listing:
#include <vector>
#include <unordered_set>
struct Point2f
{
float x;
float y;
Point2f(float a, float b) : x(a), y(b) {}
Point2f() : x(0), y(0) {}
};
bool operator==(const Point2f& pt1, const Point2f& pt2)
{
return ((pt1.x == pt2.x) && (pt1.y == pt2.y));
}
namespace std
{
template<>
struct hash<Point2f>
{
size_t operator()(Point2f const& pt) const
{
return (size_t)(pt.x*100 + pt.y);
}
};
}
void removedupes(std::vector<Point2f> & vec)
{
std::unordered_set<Point2f> pointset;
auto itor = vec.begin();
while (itor != vec.end())
{
if (pointset.find(*itor) != pointset.end())
{
itor = vec.erase(itor);
}
else
{
pointset.insert(*itor);
itor++;
}
}
}
int main(int argc, char* argv[])
{
std::vector<Point2f> pointTemp;
pointTemp.resize(6);
pointTemp[0]=Point2f(1,1);
pointTemp[1]=Point2f(2,3);
pointTemp[2]=Point2f(1,1);
pointTemp[3]=Point2f(2,3);
pointTemp[4]=Point2f(1,1);
pointTemp[5]=Point2f(4,1);
removedupes(pointTemp);
return 0;
}
This can be done by first sorting the points (using std::sort) then eliminating the duplicated points (using std::unique). To do that, you will need a function compare()
#include <algorithm>
// Lexicographic compare, same as for ordering words in a dictionnary:
// test first 'letter of the word' (x coordinate), if same, test
// second 'letter' (y coordinate).
bool lexico_compare(const Point2f& p1, const Point2f& p2) {
if(p1.x < p2.x) { return true; }
if(p1.x > p2.x) { return false; }
return (p1.y < p2.y);
}
bool points_are_equal(const Point2f& p1, const Point2f& p2) {
return ((p1.x == p2.x) && (p1.y == p2.y));
}
void remove_duplicates(std::vector<Point2f>& points) {
// Note: std::unique leaves a 'queue' of duplicated elements
// at the end of the vector, and returns an iterator that indicates
// where to stop (and where to 'erase' the queue)
std::sort(points.begin(), points.end(), lexico_compare);
points.erase(std::unique(points.begin(), points.end(), points_are_equal), points.end());
}
Note1: you can make the code shorter by using C++0x11 lambdas instead of the two functions lexico_compare and points_are_equal.
Note2: if you need to keep the order of the points, you can do an indirect sort instead, and keep track of which points are duplicated.
#include <iostream>
#include <vector>
#include <iterator>
#include <algorithm>
struct Point2f
{
float x;
float y;
};
int main(int argc, char const *argv[])
{
std::vector<Point2f> points =
{
{1, 1}, {2, 3}, {1, 1}, {2, 3}, {1, 1}, {4, 1}
};
auto print = [&]()
{
for (const auto &point : points)
{
std::cout << "(" << point.x << " " << point.y << ") ";
}
std::cout << std::endl;
};
// first sort
std::sort(points.begin(), points.end(), [](const Point2f & lhs, const Point2f & rhs)
{
return lhs.x < rhs.x && lhs.y < rhs.y;
});
// print
print();
// remove duplicated element
auto it = std::unique(points.begin(), points.end(), [](const Point2f & lhs, const Point2f & rhs)
{
return lhs.x == rhs.x && lhs.y == rhs.y;
});
points.resize(std::distance(points.begin(), it));
// print
print();
return 0;
}
Please be careful with the equal function
. If we aim to tick out similar
enough points, we should use a hash that gives the same hash value for similar
points and an approximate-equal
that group the similar points
as the same. In my case I use the following:
# include <iostream>
# include <vector>
# include <unordered_set>
# include <utility>
# include <Eigen/Dense>
const std::string red("\033[0;31m");
const std::string green("\033[1;32m");
const std::string yellow("\033[1;33m");
const std::string cyan("\033[0;36m");
const std::string magenta("\033[0;35m");
const std::string reset("\033[0m");
struct ApproxHash
{
std::size_t operator() (Eigen::Vector2d const& pt) const
{
size_t score = (size_t)(pt.x()*100) + (size_t)(pt.y()*10);
std::cerr <<"Point: "<< pt.transpose()<< " has score: "<<score<<std::endl;
return score;
}
};
struct ApproxEqual{
// This is used to guarantee that no duplicates should happen when the hash collision happens.
public:
bool operator()(const Eigen::Vector2d & pt1, const Eigen::Vector2d & pt2) const {
double threshold = 0.00001;
bool xdiff = fabs(pt1.x() - pt2.x())<threshold;
bool ydiff = fabs(pt1.y() - pt2.y())<threshold;
bool result = (fabs(pt1.x() - pt2.x())<threshold) && (fabs(pt1.y() - pt2.y())<threshold);
std::cerr<<cyan<<"Equal is called for: "<< pt1.transpose()<<" and "<<pt2.transpose()<<" which are " << result<<" equal. "<<" xdiff"<< xdiff<<", ydiff"<<ydiff<<reset<<std::endl;
return result;
}
};
void removeDuplicates(std::vector<Eigen::Vector2d>& vec)
{
// If we would like to store values, we should use std::unordered_map.
std::unordered_set<Eigen::Vector2d, ApproxHash, ApproxEqual> pointset;
auto ii = vec.begin();
while (ii != vec.end())
{
std::cerr<<"Processing: "<<ii->transpose()<<std::endl;
if (pointset.find(*ii) != pointset.end()) // O(1) lookup time for unordered_set
{
std::cerr<<red<<"Found duplicate: "<<ii->transpose()<<reset<<std::endl;
vec.erase(ii); // vec.erase returns the next valid iterator
}
else
{
pointset.insert(*ii);
std::cerr<<"Inserted: "<<ii->transpose()<<std::endl;
ii++;
}
}
} // end of removeDuplicates
int main(int argc, char* argv[])
{
std::vector<Eigen::Vector2d> pointTemp;
pointTemp.resize(15);
pointTemp[0]=Eigen::Vector2d(1.0011121213,1);
pointTemp[1]=Eigen::Vector2d(2.0,3.121);
pointTemp[2]=Eigen::Vector2d(4.004,1.0);
pointTemp[3]=Eigen::Vector2d(2.0,3.121);
pointTemp[4]=Eigen::Vector2d(1.001112121,1);
pointTemp[5]=Eigen::Vector2d(4.004,1.0);
pointTemp[6]=Eigen::Vector2d(1.2,1);
pointTemp[7]=Eigen::Vector2d(0.028297902, 0.302034);
pointTemp[8]=Eigen::Vector2d(0.028297901, 0.302034);
pointTemp[9]=Eigen::Vector2d(0.249941, 0.227669);
pointTemp[10]=Eigen::Vector2d(0.249941, 0.227669);
pointTemp[11]=Eigen::Vector2d(0.0206403, 0.304258);
pointTemp[12]=Eigen::Vector2d(0.0206403, 0.304258);
pointTemp[13]=Eigen::Vector2d(0.0206403, 0.304258);
pointTemp[14]=Eigen::Vector2d(0.0282979, 0.302034);
for (auto & point:pointTemp)
{
std::cout<<point.x()<<", "<< point.y()<<std::endl;
}
removeDuplicates(pointTemp);
std::cerr<<green<<"Cleaned vector: "<<reset<<std::endl;
for (auto & point:pointTemp)
{
std::cout<<point.x()<<", "<< point.y()<<std::endl;
}
return 0;
}
We can use g++ -std=c++11 -I /usr/include vectorHash.cpp -o vectorHash
to compile the example.
If we use an exact equal
or exact hash
, then we are unfortunately unable to pick up the similar points
.
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