Send email to many recipients

Question

I need to send an email to 100 recipients. When I send message to one recipient, it takes three seconds. And when I send it to three recipients at once, it also takes three seconds.

So I use multiple recipient to send the message faster.

def send(x, y, z):
    to = [x, y, z]
    subject="Multi Test"
    gmail_user = 'test@gmail.com'
    gmail_pwd = 'test'
    smtpserver = smtplib.SMTP("smtp.gmail.com", 587)
    smtpserver.ehlo()
    smtpserver.starttls()
    smtpserver.ehlo
    smtpserver.login(gmail_user, gmail_pwd)
    header = 'To:' + ", ".join(to) + '\n' + 'From: ' + gmail_user + '\n' + 'Subject: ' + subject + '\n'
    msg = header + '\n' + subject + '\n\n'
    smtpserver.sendmail(gmail_user, to, msg)
    smtpserver.close()

the email that i want to send message for is

1@yahoo.com, 2@yahoo.com, 3@yahoo.com....., 100@yahoo.com

so i want the script split into threes emails then send the message

or if you know another way to create script to send the message faster

Answer 1

Change your function to

def send(to):
    // ..
    header = 'To:' + ", ".join(to)

Then call it as

send(["1@yahoo.com", "2@yahoo.com", "3@yahoo.com", ..., "100@yahoo.com"])

But think about the following:

• If you do this, every recipient will know that you send the email to all other 99 recipients.
• You should use email.message to build an email. Don't just concat strings.