I wanna make a square with numbers.Something like this:
1 2 3 4
2 3 4 5
3 4 5 6
And i wrote a peace of code:
int a=input.nextInt();
for(int i=1; i<=a; i++){
for (int k=1;k<=a;k++){
int c=k+1;
int g=k+2;
System.out.println();
System.out.print(k+" ");
System.out.print(c+" ");
System.out.print(g+" ");
}
System.out.println();
the result is:
1 2 3 4
2 3 4 5
3 4 5 6
1 2 3 4
2 3 4 5
3 4 5 6
So, where is the mistake?
You are printing a full square in the second loop. The first one is producing multiple squares.
Try this code:
public static void main(String[] args) {
// int a=input.nextInt();
int a = 4;
for (int i = 1; i <= a; i++) {
for (int k = 0; k < a; k++) {
System.out.print(i + k);
System.out.print(" ");
}
System.out.println();
}
}
If you just remove your first loop it will print only one square.
int a=input.nextInt();
//for(int i=1; i<=a; i++){ comment this one
for (int k=1;k<=a;k++){
int c=k+1;
int g=k+2;
System.out.println();
System.out.print(k+" ");
System.out.print(c+" ");
System.out.print(g+" ");
}
System.out.println();
//} and this
and square will only be printed if you give input as 3.
1 2 3
2 3 4
3 4 5
for your square
public static void main (String[] args) throws java.lang.Exception
{
int a=3;
//for(int i=1; i<=a; i++){
for (int k=1;k<=a;k++){
int c=k+1;
int g=k+2;
int e=k+3;//added
System.out.println();
System.out.print(k+" ");
System.out.print(c+" ");
System.out.print(g+" ");
System.out.print(e+" ");//added
}
System.out.println();
//}
}
output:
1 2 3 4
2 3 4 5
3 4 5 6
Because a single loop will do just fine in your case.
Considering you are taking number of rows as input
your loop should run from i=1 to i<=a.
you don't need to take another loop just print i,i+1,i+2,i+3 inside the loop.
Try This
public static void main(String[] args) {
int a = 4;
for (int i = 1; i <= a-1; i++) {
for (int j = 0; j < a; j++) {
System.out.print(i + j);
System.out.print(" ");
}
System.out.println();
}
}
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