I have a form that displays a drop down for a foreignkey field. The form saves the users selection, however I want the view to update the database entry rather than inserting a new one. Whats the best way to go about this?
Current function:
def formset_valid(self, formset):
self.object = formset.save()
self.object.save()
return HttpResponseRedirect(self.get_success_url())
I have tried something like this:
d = RevisionDefaultType.objects.get(id=1)
n = RevisionSettings.objects.get(self.object)
d.defaultrevisiontype = n
d.save()
But it throws an error that the data being updated is not an instance.
You must add force_update=True
to your save()
function.
For more info about How Django knows to UPDATE vs. INSERT see this link in django's documentation.
I managed to tweak the update example from https://docs.djangoproject.com/en/dev/topics/db/queries/#saving-foreignkey-and-manytomanyfield-fields . This seems to be working as desired.
def formset_valid(self, formset):
self.object = formset.save(commit=False)
revdefault = RevisionDefaultType.objects.get(pk=1)
revget = RevisionSettings.objects.get(global_revision_type=self.object)
revdefault.defaultrevisiontype = revget
revdefault.save()
return HttpResponseRedirect(self.get_success_url())
Thanks again for the help.
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