Getting all variables declared in a scope - C++

Question

Is it possible to make a struct or class in C++ to get a list of the defined variables declared within a scope in C++. I don't want to hard-code these arrays.

For example, I have:

int a;
int b;
int c;
int d;

How can I get my program to print out what all the integers are in a program?

I want to be able to find the integers in the program that are incremented by one. (allints)++?

Answer 1

At some stage, you'll need to hardcode it. You can create a class that contains your ints and make a function to autoincrement all by one.

Something like:

class allints {
    int a, b, c, d;
    public:
        void autoincrement() {
            ++a, ++b, ++c, ++d;
        }
}

Or simply a vector of ints and loop it to autoincrement, as following:

allints = vector<int> (4, 0); //size 4, at the start value of 0.

void autoincrement(vector<int> v) {
    for(int i: v) ++i;
}

EDIT:

Noticing that you would be using structs or Classes, just group them in a vector and iterate them (like my 2nd example above)

Answer 2

If one needs to iterate over a bunch of objects of the same type the typical data structure one uses is an array (old school) or a collection of some kind, depending on secondary requirements like uniqueness, sortedness etc. (new school). This would work with arrays of built-in types as well as with arrays of structs.

Answer 3

Inside the class constructor I do vectorofPlatforms.pushback(this);

I have posted my own answer as none of you had thought of this approach, but I've giving you upvotes for your nice answers.