drop down only shows single value i have multiple value in my database

Question

This my code, using tables upload-data , login , paper

 <!doctype html>
    <html><head><meta charset="utf-8">
    <title>Untitled Document</title>
    </head><body>
    <table border="3"><tr>
    <th>Paper id</th>
    <th>Paper Name</th>
    <th>Reviewer Name</th>
    <th>Paper Status</th>
    </tr>
    <?php $con=mysql_connect("localhost","root","");
            mysql_select_db("conferencedb");
            $qry="select paperid,papername from paper";
            $rs=mysql_query($qry);

            $qry1="select (`username`) from login where type='reviewer'";
            $rs1=mysql_query($qry1);


            while($row=mysql_fetch_row($rs))
            {
                if($row1=mysql_fetch_row($rs1))
                {

                    echo "<tr>";
                    echo "<td>$row[0]</td>";
                    echo "<td>$row[1]</td>";
                    echo "<td><select name='type'>

only single option can fetch from the database

                        <option value='$row1[0]'>$row1[0]</option>
                    </select></td>";
                    echo "<td>Pending</td>";
                    echo "</tr>";
                } 
            }
    ?>


    </table>
    <input type="submit">
    </body>
    </html>

above code is working ,but it retrieve only single row from the database: $row1[0]; The current output window...i just marked area using paint.

Answer 1

mysql_fetch_row fetches 1 row at a time.

So if you want to get multiple rows use

while($row1=mysql_fetch_row($rs1))

instead of

if($row1=mysql_fetch_row($rs1))

OR

EDIT FOR USING MYSQLi

If you could switch to MySQLi you could use:

<?php $con=mysqli_connect("localhost","root","");
            mysqli_select_db("conferencedb");
            $qry="select paperid,papername from paper";
            $rs=mysqli_query($qry);

            $qry1="select (`username`) from login where type='reviewer'";
            $rs1=mysqli_query($qry1);


            while($row=mysqli_fetch_row($rs))
            {
               if($row1= mysqli_fetch_all ($rs1, MYSQLI_ASSOC))
                {

                    echo "<tr>";
                    echo "<td>$row[0]</td>";
                    echo "<td>$row[1]</td>";
                    echo "<td><select name='type'>

mysqli_fetch_all will fetch all the result rows of the SELECT statement as an array of rows.

EDIT FOR MULTIPLE OPTIONS INSIDE SELECT

Also

 echo "<td><select name='type'> 
    <option value='$row1[0]'>$row1[0]</option>
</select></td>";

will always give you one option tag.

echo "<td><select name='type'>";
foreach($_row1 in $row1){
        echo "<option value='$_row1[0]'>$_row1[0]</option>";
     }
        echo "</select></td>";
        echo "<td>Pending</td>";
        echo "</tr>";
    } 
   }
  ?>


    </table>
    <input type="submit">
    </body>
    </html>

Answer 2

Can you try it? You are using two arrays in one loop. So I doing like this

And, I don't know whther we can do like this $row[0]['column'],$row[1]['column']???

       while($row=mysql_fetch_row($rs))
        {
        if($row1=mysql_fetch_row($rs1))
        {

to only

       $count=0;
       while($row=mysql_fetch_array($rs))
        {
          echo $paperid=mysql_result($rs,$count,'paperid');
          echo $papername=mysql_result($rs,$count,'papername');
          echo $username=mysql_result($rs1,$count,'username');               
          $count=$count+1;

drop down only shows single value i have multiple value in my database

Question

2 answers

solution1
0 2014-09-04 12:11:20

solution2
0 2014-09-04 12:14:01

drop down only shows single value i have multiple value in my database

Question

2 answers

solution1 0 2014-09-04 12:11:20

solution2 0 2014-09-04 12:14:01

solution1
0 2014-09-04 12:11:20

solution2
0 2014-09-04 12:14:01