In Excel =2*NORMSDIST(2)
puts out ~1.96. How do I get that same value in R?
If you want to get the two-sided 95% confidence limit for a z-score, you would use =NORMSINV(0.975)
(which is =NORMSINV(1 - (1-0.95)/2)
). The fact that your formula gives approximately the same number is nothing more than a coincidence.
The equivalent in R would be qnorm(0.975)
or qnorm(1 - (1-0.95)/2)
.
You can get that value in R with
2*pnorm(2)
The pnorm()
function is the cumulative density function for a normal random variable
Which is consistent with the description of the Excel NORMDIST
function
NORMSDIST(z) returns the probability that the observed value of a standard normal random variable will be less than or equal to z. A standard normal random variable has mean 0 and standard deviation 1 (and also variance 1 because variance = standard deviation squared).
R Equivalent for =NORMSDIST(2)
is pnorm(2)
R Equivalent for =NORMSINV(0.95)
is qnorm(0.95)
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